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saw5 [17]
3 years ago
7

Explain how friction keeps a nail in place in a block of wood. If you try pull out the nail which way does friction act?

Physics
1 answer:
Bess [88]3 years ago
8 0

Answer:

Opposite to the direction that you are pulling

Explanation:

Static friction acts in the opposite direction to the acceleration.

Kinetic friction acts in the opposite direction to the velocity.

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If the child pulls with a force of 20 N for 12.0 m , and the handle of the wagon is inclined at an angle of 25 ∘ above the horiz
lilavasa [31]

Answer: 217.52 N

Explanation: The applied force is 20 N, the distance covered is 12.0 m and the angle is 25° above the horizontal.

Hence the formulae that defines work done is given by

W = Force × distance

But since the force has been inclined at an angle θ above the horizontal, the horizontal component of force is neccesary to produce the required motion to make the child do work on the wagon.

Hence

Work done = (horizontal component of force) × distance

Work done = F cos θ × distance

Work done = 20 cos 25 × 12 = 217.52 N

4 0
3 years ago
A ball strikes a wall. It exerts a force of 10 N to the left against the wall and bounces off. What force does the wall exert on
Galina-37 [17]
The wall exerts a force of equal magnitude but in the opposite direction. So the force by the wall is 10 N to the right.
6 0
3 years ago
Read 2 more answers
Whats the net force​
zavuch27 [327]

Answer:

13n pushing left

Explanation:

1563 - 1550

3 0
3 years ago
Answer this plsss<br> A mobile phone operates at 900 MHz. <br> What wavelength does it use?
Aleks [24]

Answer:

The wavelength = 0.3333 meters at 900 MHz, therefore, = /4 = 0.08333 meters.

7 0
3 years ago
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

W_2 = Fdcos\theta

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W_2= -20 J

Now total work done on sled

W_{net}= W_1 + W2

W_{net} = 57.96 - 20 = 37.96 J

7 0
3 years ago
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