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lina2011 [118]
4 years ago
12

How do you solve x+(2x + 40) + (3x - 50) = 15002

Mathematics
2 answers:
alina1380 [7]4 years ago
6 0
1. Take away the parentheses. x+2x+40+3x-50=15002

2. Add the X’s together.
x+2x+3x= 6x —> 6x+40-50=15002

3. Subtract 50 from 40.
40-50= -10 —> 6x-10=15002

4. Move -10 to the right hand side to make it positive.
6x=15002+10

5. Add 15002 and 10 together.
6x=15012

6. Divide 15012 by 6. Which makes the answer X=2502
brilliants [131]4 years ago
4 0

Answer:

First, combine like terms by combining the variables and constants. Then use properties of equality to isolate the variable and find the value for x.

Step-by-step explanation:

sample response from ed2020

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Negative 5.4 + x = 12.2. Minus 5.4. x = 6.8.<br> What error, if any, did she make?
lisabon 2012 [21]

Answer:

The answer is correct x =6.8, if she made an error, it might have been the steps she took.

Step-by-step explanation:

5.4 + x = 12.2

subtract 5.4 from both sides to put x terms on the left hand side, numerical number terms on the right hand side

5.4 - 5.4 + x = 12.2 - 5.4

x = 6.8

3 0
3 years ago
The sum of two numbers is
lara [203]
Answer:
The larger number is 60
The smaller number is 14

Explanation:
Assume that the larger number is x and that the smaller number id y.

We are given that:
1- The sum of the two numbers is 74. This means that:
x + y = 74
This equation can be rewritten as:
x = 74 - y .............> I
2- Four times the smaller number (4y) subtracted from the larger number (x), the result would be 4. This means that:
x - 4y = 4 ..............> II

Substitute with I in II and solve for y as follows:
x - 4y = 4
74 - y - 4y = 4
74 - 5y = 4
5y = 70
y = 70/5
y = 14

Substitute with the value of y in equation I to get x as follows:
x = 74 - y
x = 74 - 14
x = 60

Hope this helps :)
6 0
3 years ago
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Delvig [45]

Answer:

D) 20⁰

Step-by-step explanation:

EDF = 180-100=80⁰

EFD= 80⁰+80⁰=160⁰

180⁰-160⁰=20⁰

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3 years ago
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katen-ka-za [31]
Step 2, she didn't multiply 8 by 0.75.

Hope this helps :)
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Answer:

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3 years ago
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