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Dominik [7]
3 years ago
13

Remy wonders if the height of the mountain has anything to do with the eventual size of the tsunami wave. How should Remy test t

his? A. Cause avalanches on several different mountains and see how large each resulting tsunami is. B. Build different-sized model mountains at the edge of a pool, pour sand down the side of each mountain, and see how large each resulting wave is. C. Pour different amounts of sand down the side of a model mountain into a pool and see how large each resulting wave is. D. Build a model town at the edge of a pool and see how large waves must be to cause damage to the buildings.
Physics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

<em>The answer is B</em>

Explanation:

<em>I got this from study island</em>

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Please help as quick as possible
hjlf

Answer:

  1. 35 knots
  2. 5 knots
  3. calm
  4. 50 knots
  5. 20 knots
6 0
3 years ago
Read 2 more answers
• Describe the importance of a commonly used measuring system. Be prepared to give two examples of why having a common system of
IrinaVladis [17]
Metric system. important because it saves us time due to the fact that we do not have to convert our units every time. 
3 0
3 years ago
A train is moving in the positive direction down a track. First the train speeds up, and then it slows down. What is its acceler
tatuchka [14]
C.

The train first sped up, giving it a positive acceleration in the beginning. This eliminates D since that choice states that it begins with a negative acceleration. This also eliminates B since that choice states that the train only had a negation acceleration.

Next, the train slows down, giving it a negative acceleration. We’re looking for the answer choice that starts with a positive acceleration and ends with a negative one. This makes C the correct answer. Hope this helps!
8 0
3 years ago
Read 2 more answers
A 50-cm-long spring is suspended from the ceiling. A 330 g mass is connected to the end and held at rest with the spring unstret
Nataly [62]

Answer:

a)32.34 N/m

b)10cm

c)1.6 Hz

Explanation:

Let 'k' represent spring constant

'm' mass of the object= 330g =>0.33kg

a) in order to find spring constant 'k', we apply Newton's second law to the equilibrium position 10cm below the release point.

ΣF=kx-mg=0

k=mg / x

k= (0.33 x 9.8)/ 0.1

k= 32.34 N/m

b) The amplitude, A, is the distance from the equilibrium (or center) point of motion to either its lowest or highest point (end points). The amplitude, therefore, is half of the total distance covered by the oscillating object.

Therefore, amplitude of the oscillation is 10cm

c)frequency of the oscillation can be determined by,

f= 1/2π \sqrt{\frac{k}{m} }

f= 1/2π \sqrt{\frac{32.34}{0.33} }

f= 1.57

f≈ 1.6 Hz

Therefore,  the frequency of the oscillation is 1.6 Hz

5 0
4 years ago
According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?
ohaa [14]

Answer:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, <u>the attraction or repulsion becomes weaker</u>, decreasing to one-fourth of the original value.

Explanation:

Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.

Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.

Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is F=k\frac{q_{1}q_{2}   }{r^{2} }.

F is the force.

k is the Coulomb's constant (8.987*10^{9} \frac{Nm^{2} }{C^{2} }).

q_{1} is the electric charge of object 1.

q_{2} is the electric charge of object 2.

r is the distance between the two charges.

Electric force is inversely proportional to (r^{2}) instead of (r). As the distance between charges increases, the electric force decreases by a factor of \frac{1}{r^{2} }.

8 0
3 years ago
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