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denis-greek [22]
3 years ago
15

Examples of sources of physical entropy for secure random number generation include:________

Physics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

Noise in the environment

Electrons emitted via the photoelectric effect

Explanation:

Physical entropy can be seen as a disorderliness that can be observed in a physical system. The noise in a physical system can be used for secure number generation because of its randomness.

Noise is known to have no defined pattern and hence, can be used to creates secure random key generations.

Electrons emitted via the photoelectric effect: Electrons are emitted in a random order whenever a beam of light is incident on a photoelectric material. These electrons emitted can be used for random key generations

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What determines the frequency of an electromagnetic wave
Ostrovityanka [42]

<h2>The frequency depends upon the source energy of electromagnetic waves</h2>

Explanation:

The energy of electromagnetic  wave is

E  = h ν

E is the energy of source emitting the waves

here h is Plank's constant

and ν is used for the frequency of the electromagnetic wave

Thus the frequency of wave depends upon the energy of electromagnetic source . Because h is constant .

5 0
3 years ago
A small metal ball is given a negative charge, then brought near to end a of the rod (figure 1). What happens to end a of the ro
erma4kov [3.2K]

What happens to end a of the rod when the ball approaches it closely this first time is; It is strongly attracted.

<h3>Electrostatics</h3>

I have attached the image of the rod.

We are told that the ball is much closer to the end of the rod than the length of the rod. Thus, if we point down the rod several times, the distance of approach will experience no electric field and as such the charge on end point A of the rod must be comparable in magnitude to the charge on the ball.

This means that their fields will cancel.

Finally, we can conclude that when a charge is brought close to a conductor, the opposite charges will all navigate to the point that is closest to the charge and as a result, a strong attraction will be created.

This also applies to a strong conducting rod and therefore it is strongly attracted.

Read more about Electrostatics at; brainly.com/question/18108470

7 0
2 years ago
A toy cork gun contains a spring whose spring constant is 10.0N/m. The spring is compressed 5.00cm and then used to propel a 6.0
valentina_108 [34]

Answer:

The muzzle velocity of this cork is 2 m/s.                                

Explanation:

It is given that,

Spring constant of the spring, k = 10 N/m

Mass of the cork, m = 6 g = 0.006 kg

Initial position of the spring, x = 5 cm = 0.05 m

Final position of the spring, x' = 1 cm = 0.01 m

According to the law of conservation of energy, the initial potential energy of the spring is equal to the sum of final spring potential energy and the kinetic energy of cork such that,

\dfrac{1}{2}kx^2=\dfrac{1}{2}kx'^2+\dfrac{1}{2}mv^2

v is the muzzle velocity of this cork.

kx^2=kx'^2+mv^2      

v=\sqrt{\dfrac{k(x^2-x'^2)}{m}}

v=\sqrt{\dfrac{10\times ((0.05)^2-(0.01)^2)}{0.006}}

v = 2 m/s

So, the muzzle velocity of this cork is 2 m/s. Hence, this is the required solution.

4 0
4 years ago
Read 2 more answers
A potter's wheel rotating at 215 rev/min is switched off and rotates through 75.0 revolutions prior to coming to rest. What is t
vaieri [72.5K]

Explanation:

Given :

Initial angular velocity =w_i= 215 rev/min

Final angular velocity =w_f= 0

Number of revolutions=n =75.0 rev

Using relation

w_f^2-w_i^2=2\alpha n

0-215^2=2\times 75\alpha

-308.1666 rev/min^2=\alpha

Converting to rad/s^2

\alpha =-1.45 rad/s^2

6 0
3 years ago
During intercourse, Lydia constantly worries whether her partner thinks she is
Misha Larkins [42]
Answer is c spectatoring
6 0
3 years ago
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