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sergeinik [125]
3 years ago
9

3.7.6. A satellite is in a circular orbit around the Earth. If it is at an altitude equal to twice the radius of the Earth, 2RE,

how does its speed v relate to the Earth's radius RE, and the magnitude g of the acceleration due to gravity on the Earth's surface?a)b)c)d)e)
Physics
1 answer:
salantis [7]3 years ago
6 0

Answer:

Explanation:

For acceleration due to gravity

g = GM / R²  ---------------------------- ( 1 )

At height 2R , radius of orbit is 3R .

If speed of satellite be v

m v² / 3R = GMm / (3R)² ( centripetal force = gravitational force )

v² = GM / 3R -------------------------------------- ( 2 )

Dividing (1) and (2)

v² / g = R / 3

v² = gR / 3

v = √( gR / 3 )

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klio [65]
The answer is D. Sound insulators prevent sound from being transmitted better than elastic solids because sound insulators basically muffle and block the sound waves.

5 0
2 years ago
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the gravitational force exerted on a baseball is 2.21 N down, a pitcher throws the ball horizontally with velocity 18.0 m/s by u
Ilia_Sergeevich [38]
To have a weight of 2.21N., the ball's mass is (2.21/9.8) = .226kg. 
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<span>b) Acceleration of the ball = (v/t), = 18/.17, = 105.88m/sec^2. </span>
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8 0
3 years ago
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The mass of the car?
Nonamiya [84]

Answer:

1050 kg

Explanation:

The formula for kinetic energy is:

KE (kinetic energy) = 1/2 × m × v² where <em>m</em> is the <em>mass in kg </em>and <em>v</em> is the velocity or <em>speed</em> of the object <em>in m/s</em>.

We can now substitute the values we know into this equation.

KE = 472 500 J and v = 30 m/s:

472 500 = 1/2 × m × 30²

Next, we can rearrange the equation to make m the subject and solve for m:

m = 472 500 ÷ (1/2 × 30²)

m = 472 500 ÷ 450

m = 1050 kg

Hope this helps!

3 0
1 year ago
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a crate is being lifted into a truck. if it is moved with a 2470n force and 3650 j of work is done , then how far is the crate b
SVEN [57.7K]

Answer:

The crate was being lifted by a height of 1.48 meters.

Explanation:

In an attempt o move a crate;

Force applied = 2470 N

Work done by the force = 3650 J

We know that the work done is defined as the force used to move an object to a distance.

Given the Force used and the work done by that Force, we need to find out the distance the crate was lifted to.

Work done is defined as:

Work = Force*distance covered in the direction of the force

3650 = 2470*distance

distance = 3650/2470

distance = 1.48 meters

4 0
3 years ago
Please help me with this
Firlakuza [10]

Answer:

can't see anything sorry can't help

7 0
2 years ago
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