Answer: option 1) <span>
2Cr3+(aq)+6Cl-(aq) ------> 2Cr(s)+3Cl2(g)Explanation:1) Write the oxidation half-reaction:
2) Write the reduction half-raction:
3) Multiply each half-reaction by the appropiate coefficient to equal the number of electrons of both half-reactions.
4) Add both half-reactions
And that is the answer. You can count the atoms and charges on every side and check they are equal.
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Answer:
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At STP, P = 1 atm, and T = 0 C
Thus, PV = nRT => V = nR(273). We will use this later...
if you have 35.4 Ca, and the molar mass of Ca is 40.08, you get .883 moles Ca. Thus, since it takes 2 moles of Ca to form a reaction, you only need half the moles of Ca of O2. Thus, n(O2) = .883/2
Tie this back to the first equation and you get
V = .442 * <span>0.082057(which is R) * 273 = 9.9 L</span>