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GREYUIT [131]
3 years ago
12

Scientists are experimenting with a king of gun that may eventually be used to fire payloads directly into orbit. In one test, t

his gun accelerates a 5.0kg projectile from rest to speed of 4.0 x 10^3 m / s. The net force accelerating the projectile is 4.9 x 10^5N. How much time is required for the projectile to come up to speed?

Physics
1 answer:
olasank [31]3 years ago
7 0
Here are some equations to use.

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If the weight of displaced liquid and the weight of an object are the same, the object will:
liberstina [14]

Answer:

c

Explanation:

I think but if I'm wrong I'm sorry

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3 years ago
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Three charges are arranged as shown in the picture above. Find the magnitude and direction of the electrostatic force on the 6 n
bagirrra123 [75]

Answer:

Bot Nm

Explanation:

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3 years ago
What is the sequence of energy transformations from the moment the ball is dropped to the moment the board is bent to its maximu
Mila [183]

Answer:

B

Explanation:

Transformation of energy involves conversion of energy from one form to another for example our movement around involves the conversion of chemical energy stored in the food we eat to other forms of energy such as kinetic energy for the movement, electrical energy in the neurons for impulses and others

The ball posses gravitational potential energy since it is held at a displacement to the ground ( zero point) and when released, the gravitational potential energy is converted to kinetic energy which leads to the fall of the ball until it is at zero displacement to the earth. The board likewise when bent to its maximum extent stored elastic potential energy as a result of the partial displacement of its constituent particle provided it is  not stretch beyond its elastic limit which can lead to deformation of the board and the elastic potential energy lost.

5 0
4 years ago
Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces
Mandarinka [93]

Answer: 0.81\times 10^{16} beta particles

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 14.0 g

Molar mass = 137 g/mol

\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of cesium contains atoms =  6.023\times 10^{23}

0.102 moles of cesium contains atoms =  \frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}

The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

t = time taken for decay = 3 minutes

{t_{\frac{1}{2}}} = half life = 30.0 years = 1.577\times 10^7 minutes

The fraction that decays  :  1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}

Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

Thus 0.81\times 10^{16} beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

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3 years ago
Which wave characteristic determines color?
Veseljchak [2.6K]
I would said A is the best option if i’m wrong sorry
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3 years ago
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