Answer:
1. Slope = 53.3 x 10⁻⁶
2. Deflection = -0.00016m
Explanation:
given:
let L = 4 m (span of cantilever beam)
let w = 300 N/m (distributed load)
let EI =60 MNm² (flexural stiffness)
dy w * L³ 300 x 4³
1. slope = ------- = --------- = ------------------- = 53.3 x 10⁻⁶
dx 6EI 6 x 60x10⁶
wL⁴ 300 x 4⁴
2. Deflection = y = - ----------- = - ------------------ = -0.00016m
8EI 8 x 60x10⁶
therefore the deflection is 0.16mm downwards.
Answer:
the maximum height h to which the the water steam could rise is 40.65m
Explanation:
Given;
= 20m,
= 2atm ≈ 20265 N/m
Density of water ρ = 1000 kg/
Note: we take point 1 at the free surface of the water in the tank and point 2 at the top of the water trajectory. we also take reference level at the bottom of the tank.
fluid velocity at the free surface of tank is very low (
≅ 0) and at the top of the water trajectory
= 0
Step 1: Applying Bernoulli equation between poin 1 and point 2
/ρg +
/2g +
=
/ρg +
/2g + 
/ρg +
=
/ρg + 
= (
-
)/ρg + 
Substituting values into
we have,
= 
Answer:
Explanation:
Given
scale i.e. 
Using Reynolds number similarity


Properties of air

Properties of sea water




