Answer:
Elemental gold to have a Face-centered cubic structure.
Explanation:
From the information given:
Radius of gold = 144 pm
Its density = 19.32 g/cm³
Assuming the structure is a face-centered cubic structure, we can determine the density of the crystal by using the following:
a = 407 pm
In a unit cell, Volume (V) = a³
V = (407 pm)³
V = 6.74 × 10⁷ pm³
V = 6.74 × 10⁻²³ cm³
Recall that:
Net no. of an atom in an FCC unit cell = 4
Thus;
density d = 19.41 g/cm³
Similarly; For a body-centered cubic structure
where;
r = 144
a = 332.56 pm
In a unit cell, Volume V = a³
V = (332.56 pm)³
V = 3.68 × 10⁷ pm³
V 3.68 × 10⁻²³ cm³
Recall that:
Net no. of atoms in BCC cell = 2
∴
density =17.78 g/cm³
From the two calculate densities, we will realize that the density in the face-centered cubic structure is closer to the given density.
This makes the elemental gold to have a Face-centered cubic structure.
Explanation:
Equation of reaction:
CO + 2H₂ ⇒ CH₃OH + energy
a. An increase in pressure:
A change in pressure affects only equilibrium involving a gas or gases. Le Chatelier's principle can be used to predict the direction of displacement.
An increase in pressure on an equilibrium system will shift the position of equilibrium to the side having smaller volume and vice-versa
CO + 2H₂ ⇒ CH₃OH + energy
3 moles 1 moles
An increase in pressure will favor the forward reaction to be favored.
b. Addition of H₂:
An in concentration of a specie favors the direction that uses up that specie and lowers its concentration.
Addition of hydrogen gas increases the concentration of amount of substances reacting.
To annul the effect of the reactant, more the product is given. The equilibrium shifts in the forward direction.
learn more:
equilibrium brainly.com/question/5877801
#learnwithBrainly
(19.78 x 10) + (80.22 x 11) all of them divided by 100= 10.81 amu
In a redox chemical reaction, one species gets reduced and another gets oxidized. Manganese element is reduced in this reaction.
<h3>What is oxidized and reduced?</h3>
In a redox reaction, the increase or decrease in the oxidation number and electrons results in the reduction and oxidation of the chemical species. The oxidation and reduction occur simultaneously in a reaction.
The oxidation number of Mn in permanganate ion was +8 on the left side and decreased to +4 on the right side of the equation. Potassium permanganate is an oxidizing agent that has reduced the manganese ion of the permanganate ion.
Therefore, manganese is reduced.
Learn more about reduction and oxidation here:
brainly.com/question/2427143
#SPJ4
