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Furkat [3]
3 years ago
6

When 2-heptyne was treated with aqueous sulfuric acid containing mercury(II) sulfate, two products, each having the molecular fo

rmula C7H14O, were obtained in approximately equal amounts. What are these two compounds?

Chemistry
1 answer:
xeze [42]3 years ago
3 0

Answer:

See explanation below

Explanation:

This is a reaction of alkyne hydration. We have aqueous sulfuric acid in HgSO4. This reagent is used to convert a alkyne into a ketone. The mechanism of reaction is taking place in 4 steps.

The first step is an electrophilic adition where the atom of Hydrogen that the acid provides, is added to the alkyne in the triple bond.

In this step, as Carbon 2 and Carbon 3, do not have any atom of hydrogen, the adition of this hydrogen could take place in either carbon 2 or carbon 3, that's why at the end you can have two products in equal amounts.

The second step is the adition of one molecule of water in the carbocation that appears in the previous step.

The third step, is an acid base equilibrium, where the hydrogen atom from the water that added to the heptene, is substracted (In this case by the conjugate base of the acid).

In this way, we will have an alcohol with a double bond. This is the enolic form of the molecule.

The final step is a tautomeric equilibrium, where the double bond of the C = C will pass to a double bond C = O forming a carbonile and therefore, a ketone.

If this was done in carbon 2 from step 1, you'll have the 2-heptanone. If it were on carbon 3, it will be the 3 - Heptanone.

Picture attached has the mechanism and products.

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For the following balanced equation: 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O(l) a) How many moles of HNO3 will r
s344n2d4d5 [400]

Answer:

a) <u>26.67 moles HNO3 </u>

b) <u>0.33 moles NO</u>

c) <u>0.40 moles NO is produced</u>

d)<u>.157 moles Cu</u>

e) <u>0.105 moles NO</u>

f) <u>26.4 grams HNO3</u>

g) <u>Cu is in excess</u>

h) <u>2.41 grams Cu remain</u>

i) <u>2.37 grams NO</u>

Explanation:

Step 1: Data given

Molar mass of Cu = 63.55 g/mol

Molar mass of HNO3 = 63.01 g/mol

Molar mass of Cu(NO3)2 = 187.56 g/mol

Molar mass of NO = 30.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O(l)

a) How many moles of HNO3 will react with 10 moles of Cu?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 10 moles Cu we need 8/3 *10 = <u>26.67 moles HNO3 </u>

b) How many moles of NO will form if 0.50 moles of Cu reacts?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.50 moles Cu we'll have 2/3 *0.50 = <u>0.33 moles NO</u>

c) If 0.80 moles of H2O forms, how much NO must also form?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

If 0.80 moles H2O is produced, 0.80/2 = <u>0.40 moles NO is produced</u>

d) How many moles of Cu are in 10.0 grams of Cu?

Moles Cu = 10.0 grams / 63.55 g/mol = 0.157 moles

In 10.0 grams Cu we have <u>0.157 moles Cu</u>

e) If 10.0 g of Cu reacts, how many moles of NO will form?

10.0 grams Cu = 0.157 moles

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.157 moles Cu we'll have 2/3 * 0.157 = <u>0.105 moles NO</u>

f) If 10.0 g of Cu reacts, how many grams of HNO3 are required?

10.0 grams Cu = 0.157 moles

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.157 moles Cu we'll need 0.419 moles HNO3

This is 0.419 moles * 63.01 g/mol = <u>26.4 grams HNO3</u>

g) If 10.0 g of Cu and 20.0 g of HNO3 are put together in a reaction vessel, which one will be in excess?

Moles Cu = 0.157 moles

Moles HNO3 = 20.0 grams / 63.01 g/mo = 0.317 moles

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

The limiting reactant is HNO3. It will completely be consumed (0.317 moles). <u>Cu is in excess.</u> There will react 3/8 * 0.317 = 0.119 moles Cu

There will remain 0.157 - 0.119 = 0.038 moles

h) How many grams of the excess substance will be left over?

There will react 3/8 * 0.317 = 0.119 moles Cu

There will remain 0.157 - 0.119 = 0.038 moles

This is 0.038 moles * 63.55 g/mol = 2.41 grams

i) How many grams of NO will form in the reaction described in part g?

For 3 moles Cu we need 8 moles HNO3 to produce 3 moles Cu(NO3)2, 2 moles NO and 4 moles H2O

For 0.317 moles HNO3 we'll have 0.317/4 = 0.0793 moles NO

This is 0.079 mol * 30.01 g/mol =<u> 2.37 grams NO</u>

3 0
3 years ago
Help on science please !!
NemiM [27]

Answer:

a. Kenya's growth seems to be a large population influx, an increase in the pre-reproductive stage.

b. There is a decrease in the younger generation, meaning that the reproductive part of the population is more than the pre-reproductive part. Which means less of an incline in population.

c. You can see the differences within the countries, that the growth rate in Kenya is extremely high, the United States more moderate, while Germany is somewhat even throughout. Germany is not growing much in comparison to Kenya.

6 0
2 years ago
Which weather condition is NOT associated with warm fronts??
slavikrds [6]

Answer:

A Winter storm usually does not come with a warm fronthey warm front.

Explanation:

When the front passes over an area it means to change in the weather. Many. Many friends cause weather events such as rain thunderstorms gusty winds tornadoes and hurricanes.

5 0
2 years ago
Will give Brainliest If Correct!
Debora [2.8K]

Answer:

Slowly changing to be slightly more evenly distributed based on humanitarian efforts. Still unevenly distributed leaving millions starving to death.

Explanation:

3 0
2 years ago
Why ammonium is not a molecular ion
In-s [12.5K]

Answer:

See below

Explanation:

Ammonium (NH_{4}^+) is not a molecular ion because it is just a poly-atomic ion. A molecular ion has a "negative or positive charge" as a whole but the positive charge on here is not on the whole. So, it is a poly-atomic ion and not molecular ion.

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3 years ago
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