Question

Pulses A, B, C, and D all travel at 10 m/s on the same string but in opposite directions. The string is depicted at time t=0 in (Figure 1). The small pulses have an amplitude of 2.0 cm, and the large pulse has an amplitude of 4.0 cm.
A) Find the displacement of point P at time t=0.10s .

B) Find the displacement of point P at time t=0.20s .

Answer 1

(a) The displacement of point P at time t=0.10s is determined as +2cm.

(b) The displacement of point P at time t=0.20s is determined as -2cm.

What is displacement?

Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.

x = vt

Displacement of the waves after 0.1 s

x = 10 m/s x 0.1 s = 1 m

Each wave will travel 1 m to the right or to the left, depending on the initial direction.

• wave B from left will stop at point 0 m
• wave A from left will stop at point -1 m
• wave C from right will stop at point 0 m
• wave D from right will stop at point + 1 m

wave B and C superimposed and the displacement will be between A and D.

Amplitude of A = - 2cm

Amplitude of D = + 4cm

Displacement of point P = 4 cm - 2 cm =  2cm

Displacement of the waves after 0.2 s

x = 10 m/s x 0.1 s = 2 m

Each wave will travel 2 m to the right or to the left, depending on the initial direction.

• wave B from left will stop at point 1 m
• wave A from left will stop at point 0 m
• wave C from right will stop at point -1 m
• wave D from right will stop at point 0 m

Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)

Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm

Learn more about displacement here: brainly.com/question/2109763

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