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ruslelena [56]
4 years ago
15

A pin fin of uniform cross-sectional area is fabricated of an aluminum alloy (k = 160W m-1 K-1 ). The fin diameter is D = 4 mm,

and the fin is exposed to convective conditions characterized by h = 220W m-2 K-1 . It is reported that the fin efficiency is ?f = 0.65. Account for convection heat transfer at the fin tip.
Questions: (a) What is the length of the fin, L?

(b) What is the fin effectiveness ?f?

Engineering
1 answer:
disa [49]4 years ago
4 0

Answer: (a) 36.18mm

(b) 23.52

Explanation: see attachment

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Different Gauss quadrature formulae predict different values for the same integral a. True b. False
scoray [572]

Answer: False

Explanation:

The given statement are false as, the gauss quadrature predicted same value only when their is a minute error at one point and two point rule. It basically given the more precise answer and the answer are only changed by the decimal place. The gauss quadrature method are basically used for calculating the certain integral.

5 0
3 years ago
A steam power plant operates on an ideal Rankine cycle with two stages of reheat and has a net power output of 120 MW. Steam ent
uysha [10]

Answer:

a) 40.6%

b)72.19kg/s

Explanation:

The Rankine cycle with two reheat stages has 9 stages in total.

The maximum pressure will be at the first inlet stage of the HP turbine which is stage 3. The minimum pressure will be the exit stage of the condenser because the condenser operates under vacuum pressure which is stage 1.

The following assumptions can be made:

1 - Each component in the cycle is analyzed as an open system operating at steady-state.

  2 - All of the processes are internally reversible.

  3 - The turbine and pump operate adiabatically and are internally reversible, so they are also isentropic.

   4 - Condensate exits the condenser as saturated liquid.

  5 - The effluent from the HP turbine is a saturated vapor.

  6 - No shaft work crosses the system boundary of the boiler or condenser.

   7 - Changes in kinetic and potential energies are negligible

a) The thermal efficiency of the cycle is defined as the work of the cycle divided by the total heat input to the system. The stages that have heat input is stages 2-3, 4-5, 6-7.

For stage 2:

s₁=s₂ assuming isentropic

s_1=0.4762 @ P_1=15MPa

enthalpy will be a compressed liquid so after interpolation

h_2=97.93+(0.4762-0.2932)((180.77-97.93)/(0.5666-0.2932))=153.38kJ/kg

For stage 3:

Superheated steam @ T=500⁰C and P=15MPa

h_3=3310.8kJ/kg

Stage 4:

superheated vapor

P=5MPa

s₃=s₄=6.3480 kJ/kg, we must use interpolation to find h₄

h_4=2925.7-(6.348-6.2111)((3069.3-2925.7)/(6.4516-6.2111))=3007.44kJ/kg

Stage 5:

Superheated steam @ T=500⁰C and P₄=P₅=5 MPa

h_5=3434.7kJ/kg

Stage 6:

Superheated steam at P₆= 1MPa

s₅=s₆

s_6=6.9781

We find h₆ using interpolation from the steam tables:

h_6=2943.1-(6.9781-6.9265)((3051.6-2943.1)/(7.1246-6.9265))=2970.67kJ/kg

Stage 7:

P₇=P₆=1MPa

T=500⁰C superheated steam

h_7=3479.1kJ/kg

The heat into the cycle is:

=(h_3-h_2)+(h_5-h_4)+(h_7-h_6)

=(3310.8-153.38)+(3434.7-3007.44)+(3479.1-2970.67)=4108.74kJ/kg

We can determine the work out by the condenser from stage 9 to stage 1:

Stage 1:

saturated liquid P=5kPa

h_1=137.75kJ/kg

Stage 9:

We assume that its a saturated liquid with quality of 1 at 5kPa and

s₇=s₉ and after interpolation

h_9=2568.53kj/kgK

Qout = [/tex]2568.53-137.75=2430.79kJ/kg[/tex]

The thermal efficiency can be written in terms of qin and qout:

n=1-(q_o/q_i)=1-2430.79/4093.11=0.4061

Efficiency of 40.61%

b)

The mass flow rate can be calculated from the Wnet:

W_n=W_t-W_p

Work of the turbines minus the work of the pumps:

W_n=m((h_3-h_4)+(h_5-h_6)+(h_7-h_9)-(h_1-h_2)

120000=m(1662.33)

m=72.19

mass flow rate of steam is 72.19 kg/s

7 0
3 years ago
In fully developed laminar flow in a circular pipe the velocity at R/2 (mid-way between the wall surface and the centerline) is
Butoxors [25]

Answer:

u_{max} = 17.334\,\frac{m}{s}

Explanation:

Let consider that velocity profile inside the circular pipe is:

u(r) = 2\cdot U_{avg} \cdot \left(1 - \frac{r^{2}}{R^{2}}  \right)

The average speed at r = \frac{1}{2} \cdot R is:

U_{avg} = \frac{13\,\frac{m}{s} }{2\cdot \left(1-\frac{1}{4}  \right)}

U_{avg} = 8.667\,\frac{m}{s}

The velocity at the center of the pipe is:

u_{max} = 2\cdot U_{avg}

u_{max} = 17.334\,\frac{m}{s}

6 0
3 years ago
Read 2 more answers
The difference in quantity between the add and full marks on an engine oil dipstick is typically
svetoff [14.1K]

Answer:

1 quart (0.9 liters).

Explanation:

A proper inspection of various systems and components in a vehicle at regular intervals is very important and necessary because it helps to ensure that the vehicle is in a safe and reliable condition.

Generally, these inspection includes tyres, lighting systems, fan belts, shock absorbers, fluid (oil and water) level, etc. If any fault or concern is detected in the course of an inspection, it should be noted for quick repair or servicing by an expert technician.

All automobile engine requires an adequate amount of engine oil as a lubricant so as to mitigate friction and enhance proper functionality of the vehicle. Thus, the proper functionality of an engine is largely dependent on the level of the engine oil; it shouldn't be too low or high.

Basically, the engine oil should be checked at regular intervals (periodically) and should be on the level indicated or chosen by the manufacturer of the vehicle.

A dipstick is designed to be used for checking the engine oil level in a vehicle and it is marked with lines indicating minimum and maximum, low and high or add and full.

The difference in quantity between the add and full marks on an engine oil dipstick is typically 1 quart (0.9 liters).

5 0
3 years ago
Multiple Choice
Ymorist [56]

Answer:

Sealing agent

Explanation:

Generally, when we have water leaks in almost any building or equipment, we use a sealant. However, this sealant could be of different types depending on the peculiarity of the leakage.

Thus, the correct answer is sealing agent.

5 0
3 years ago
Read 2 more answers
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