Answer:
can exchange energy with its surroundings through heat and work transfer. In other words, work and heat are the forms that energy can be transferred across the system boundary.
Answer:
the balls reached a height of 4.9985 m
Explanation:
Given the data in the question;
mass one m = 3.8 kg
mass two M = 2.1 kg
Initial velocities
u = 22 m/s
U = { moving downward} = 12 m/s
Now, using the law conservation of linear moment;
mu + MU = v( m + M )
we solve for "v" which is the velocity of the ball s after collision;
v = (mu + MU) / ( m + M )
so we substitute our given values into the equation
v = ( ( 3.8 × 22 ) + ( 2.1 × -12) ) / ( 3.8 + 2.1 )
v = ( 83.6 - 25.2 ) / 5.9
v = 58.4 / 5.9
v = 9.898 m/s
Now, we determine required height using the following relation;
v"² - v² = 2gh
where v" is the velocity at the top which is 0 m/s and g = -9.8 m/s²
0 - v² = 2gh
v² = -2gh
so we substitute
( 9.898 )² = -2 × -9.8 × h
97.97 = 19.6 × h
h = 97.97 / 19.6
h = 4.9985 m
Therefore, the balls reached a height of 4.9985 m
The charge distribute on the inner surface with the radius r₁ will be zero,In the region r₁<r<r₂ will also zero. While on the outer surface with radius r₂ will be -q.
<h3>What is Gauss law?</h3>
The total electric flux out of a closed surface is equal to the charge contained divided by the permittivity,
According to Gauss Law. the electric flux in a given area is calculated by multiplying the electric field by the area of the surface projected in a plane perpendicular to the field.
From the Gauss law, it is stated that the field inside the conductor is zero. Charge will lie only on the surface.
(a)The charge distribute on the inner surface with the radius r₁ will be zero.
(b) In the region r₁<r<r₂ will also zero.
(c)The outer surface with radius r₂ charge distribution will be -q.
Hence, the charge distribute on the inner surface with the radius r₁ will be zero,
To learn more about the Gauss law, refer to the link;
brainly.com/question/2854215
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Answer:
B) Depends on launch speed.
Explanation:
This is true when considering the basketball player in a given basketball game. The speed at which the player jumps up is a strong factor which determines the acceleration of his acceleration. The direct co-relation show that, speed and acceleration of the basketball player are interrelated.
Answer:
Discovered different planets.
Explanation:
