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Gnom [1K]
3 years ago
10

A chemist prepares a solution of sodium carbonate by measuring out of sodium carbonate into a volumetric flask and filling the f

lask to the mark with water. Calculate the concentration in of the chemist's sodium carbonate solution. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

The correct answer will be "9.45\times 10^{-5} \ mol/L".

Explanation:

We have:

Moles of solute (Na₂Co₃) = 18.9 \mu \ mol

                                           = 18.9\times 10^{-6}

                               1 \mu \ mol = 10^{-6} \ mol

Now,

The volume of the solution will be:

⇒  0.200 \ L

∴ {1 \ mL=0.001 \ L}

The formula to find the concentration will be:

⇒  Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}

On substituting the given values, we get

⇒                          =\frac{18.9\times 10^{-6}}{0.200}

⇒                          =9.45\times 10^{-5} \ mol/L

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What is the mass in grams of 9.76 x 10 12 atoms of naturally occurring sodium?
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The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

          if     6.02 × 10²³ atoms are found in 1 mole ofsodium
   then let  9.76 × 10¹² atoms are found in     x

⇒     x  =    (9.76 × 10¹² )  ÷  (6.02 × 10²³)

            =  1.619 × 10⁻¹¹ mol


Now, mass = moles × molar mass

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Calculate the wavelength of a football (425g) thrown by an NFL quarterback traveling at 50mph
AnnyKZ [126]

Wavelength is 6.976 x 10^ -35 m

Explanation:

In this, we can use De Broglie’s equation. This equation is the relationship between De Broglie’s wavelength, velocity and the mass of a moving object. In this equation, we are using plank's constant which is 6.626 x 10^-34 m^2 kg/s.

We know that one mile per hour is equivalent to 0.447 M/S.

And One gram is equivalent to 10^-3 kg.

De Broglie’s wavelength = λ ( wave length) = Plank’s constant/ Mass x velocity

λ ( wave length) = 6.626 x 10^ -34/ (425 x10^-3) x ( 50 x 0.447)

                                 = 6.626 x 10^ -34/ 0. 425 x 22.35

                                 = 6.626 x 10^ -34/ 9.498

                                 = 6.976 x10^ -35 m

So, the wavelength of the football will be 6.976 x 10^ -35 m

7 0
3 years ago
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