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krok68 [10]
4 years ago
6

The poh of a solution is 9.32. calculate the hydrogen ion concentration of the solution.

Chemistry
1 answer:
natima [27]4 years ago
4 0
PH+pOH=14
pOH=9.32
pH=14-pOH=14-9.32=4.68
pH=4.68

pH=-log[H⁺]
-pH= log[H⁺]

[H^{+}]= 10^{-pH} = 10^{-4.68}=2.09*10^{-5}

[H^{+}] = 2.09*10^{-5}M
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3 years ago
How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?
aksik [14]

Complete Question:

To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride. How many grams of F− must be added to a cylindrical water reservoir having a diameter of 2.02 × 102 m and a depth of 87.32 m?

Answer:

2.23x10⁶ g

Explanation:

The concentration of the fluoride (F⁻) must be 0.800 ppm, which is 0.800 parts per million, so the water must have 0.800 g of F⁻/ 1000000 g of the solution. The density of the water at room temperature is 997 kg/m³ = 997x10³ g/m³. So, the concentration of the fluoride will be:

0.800 g of F⁻/ 1000000 g of the solution * 997x10³ g/m³

0.7976 g/m³

The volume of the reservoir is the volume of the cylinder: area of the base * depth. The base is a circumference, which has an area:

A = πR², where R is the radius = 1.01x10² m (half of the diameter)

A = π*(1.01x10²)²

A = 32047 m²

The volume is then:

V = 32047 * 87.32

V = 2.7983x10⁶ m³

The mass of the F⁻ is the concentration multiplied by the volume:

m = 0.7976 * 2.7983x10⁶

m = 2.23x10⁶ g

8 0
3 years ago
Which missing item would complete this beta decay reaction?<br> PLATO
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Answer: _{-1}^0\beta

Explanation:  

General representation of an element is given as:   _Z^A\textrm{X}

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Beta decay : In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

The given reaction would be represented as:

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7 0
3 years ago
Read 2 more answers
If the half-life of C-14 is 5730 years, how much C-14 would be left from a 5000 year-old sample that started as 150 grams?
serious [3.7K]
<h3>Answer:</h3>

81.9 grams

<h3>Explanation:</h3>

From the question we are given;

  • Half-life of C-14 is 5730 years
  • Original mass of C-14 (N₀) = 150 grams
  • Time taken, t = 5000 years

We are required to determine the mass left after 5000 years

  • Using the formula;
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   t/T = 5000 yrs ÷ 5730 yrs

    = 0.873

N = 150 g ÷ 0.5^0.873

   = 150 g × 0.546

   = 81.9 g

Therefore, the mass of C-14 left after 5000 yrs is 81.9 g

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3 years ago
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