Answer:
Velocity
Explanation:
Objects in motion usually have a speed which is scalar or velocity which is a vector.
A scalar quantity is one with magnitude but has no directional attribute.
A vector quantity is one with both magnitude and directional attribute.
Speed is a scalar quantity that describes the magnitude of motion a body accrues.
Velocity is a vector quantity that describes both the magnitude of motion and the direction of motion in a body.
Answer:
the maximum is I₁ axis of rotation at the end
the minimum moment is I₂ axis of rotation at the center of mass
Explanation:
For this exercise we use the definition moment of inertia
I = ∫ r² dm
for bodies of high symmetry it is tabulated; In this case we can approximate a broomstick to a thin rod, the moment of inertia with respect to a perpendicular axis when varying are
at one end
I₁ = ⅓ mL²
in in center
I₂ =
m L²
There is another possible axis of rotation around the axis of the broom, in this case we have a solid cylinder
I₃ =
m r²
remember that the diameter of the broom is much smaller than its length, therefore this moment of inertia is very small
when examining the different moments of inertia:
the maximum is I₁ axis of rotation at the end
the minimum moment is I₂ axis of rotation at the center of mass
The pH of the solution is 0.37.
<h3>What is the pH of the solution?</h3>
We can write the equation of the reaction as;

Number of moles of
= 24/1000 * 1 = 0.024 moles
Number of moles of
= 60/1000 * 1 = 0.060 moles
Given that the reaction is 1:1, the limiting reactant is NaOH
Number of moles of NH4Cl left over = 0.060 - 0.024 = 0.036 moles
Concentration of left over NH4Cl = 0.036 moles/(24 + 60)/1000
= 0.43 moles
pH = -log(0.43)
pH = 0.37
Learn more about pH:brainly.com/question/15289741
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Answer:
A 1.5 metres per second squared B 0 C 6 0.5
b) 9m
Explanation:
a= v-a/t
a= acceleration measured in metres per second squared
v= final speed measured in metres per second
u= initial speed measured in metres per second
t= time measured in second
A
a=v-a/t
a= 3-0/2
a= 1.5 metres per second squared
Distance in a velocity time graph = area under
To calculate the distance in the first 4 seconds
You divide the graph into triangles and rectangles
Area A (triangle )= 1/2 × base × height
=1÷2 ×2×3
= 3m
Area B (rectangle)= L×B
=2×3
=6m
Area A + Area B= 3+6
= 9m