Answer:
a) equal 1, b) less than 1
Explanation:
a) the electric force is given by
Fe = q E
The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative
Proton
Fp = qE
Electron
Fe = - q E
Fp / Fe = -1
If we do not take into account the sign the relationship is equal to one (1)
b) to calculate the force we use Newton's second law
F = ma
qE = m a
a = q E / m
The mass of the proton much greater than the mass of the electron
ap = q E / 
ae = - q E / 
ap / ae =
/
=
/1600
=1/1600
It is much smaller than 1
Answer:
Using equation 2dsinФ=n*λ
given d=2.41*10^-6m
λ=512*10^-12m
θ=52.64 degrees
Answer:
8.85
Explanation:
The computation of the charge that must place on them in order to create 1000 N/C field between the plates is shown below:
We know that
E = (Q/A) ÷ E_o
1000 = Q ÷ 0.01×8.85× 10^-12
Q = 8.85 × 10^-12
So,
The answer is 8.85
The above formula should be applied so that the correct value could come
And, the same would be relevant
Answer:1.81
(a) Explanation:the turn ratio= input voltage÷output voltage.
400÷220=1.81.
Don't know how to solve b part...