The object is maintaining a constant velocity
This is a problem of conservation of momentum
Momentum before throwing the rock: m*V = 96.0 kg * 0.480 m/s = 46.08 N*s
A) man throws the rock forward
=>
rock:
m1 = 0.310 kg
V1 = 14.5 m/s, in the same direction of the sled with the man
sled and man:
m2 = 96 kg - 0.310 kg = 95.69 kg
v2 = ?
Conservation of momentum:
momentum before throw = momentum after throw
46.08N*s = 0.310kg*14.5m/s + 95.69kg*v2
=> v2 = [46.08 N*s - 0.310*14.5N*s ] / 95.69 kg = 0.434 m/s
B) man throws the rock backward
this changes the sign of the velocity, v2 = -14.5 m/s
46.08N*s = - 0.310kg*14.5m/s + 95.69kg*v2
v2 = [46.08 N*s + 0.310*14.5 N*s] / 95.69 k = 0.529 m/s
<h2>Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.</h2>
Explanation:
Density of air = 1.20 g/L = 
Size of room is 24.0m by 15.0 m by 4.0 m
Volume of room = 24 x 15 x 4 = 1440 m³
We know the equation
Mass = Volume x Density
Mass = 1440 x 1.2
Mass = 1728 kg
Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.
Heat can travel as<em> radiation</em>, even if there are no particles of matter
along the way. Which is really lucky, because that's how we get
heat from the sun. And light too.
