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viktelen [127]
3 years ago
8

Which of the following physical properties does not depend on the amount of the substance being studied?

Physics
1 answer:
JulijaS [17]3 years ago
5 0
The correct answer is D., density. Hope this helps!
You might be interested in
A 37.5 kg box initially at rest is pushed 4.05 m along a rough, horizontal floor with a constant applied horizontal force of 150
vodomira [7]

Answer:

a) 607.5 J

b) 160.531875 J

c)  0 J

d)  0 J

e) 2.925 m\s

Explanation:

The given data :-

  • Mass of the box ( m ) = 37.5 kg.
  • Displacement made by box ( x ) = 4.05 m.
  • Horizontal force ( F ) = 150 N.
  • The co-efficient of friction between box and floor ( μ ) = 0.3
  • Gravitational force ( N ) = m × g = 37.5 × 9.81 = 367.875

Solution:-

a) The work done by applied force ( W )

W = force applied × displacement = 150 × 4.05 = 607.5 J

b)  The increase in internal energy in the box-floor system due to friction.

Frictional force ( f ) = μ × N = 0.3 × 367.875 = 110.3625 N

Change in internal energy = change in kinetic energy.

ΔU = ( K.E )₂ - ( K.E )₁

Since the initial velocity is zero so the  ( K.E )₁ = 0  

ΔU = ( K.E )₂ = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

c) The work done by the normal force .

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

d)  The work done by the gravitational force.

Displacement of box vertically = 0

W = force applied × displacement = 367.875 × 0 = 0 J

e) The change in kinetic energy of the box

( K.E )₂ - ( K.E )₁ = ( K.E )₂ - 0 = ( F - f ) × ( x ) = ( 150 - 110.3625 ) × 4.05 = 160.531875 J

f) The final speed of the box

( K.E )₂ = 160.531875 J = 0.5 × 37.5 × v²

v² = 8.56

v = 2.925 m\s.

5 0
3 years ago
FIRST TO ANSWER CORRECTLY GETS BRAIBLIEST!!
WINSTONCH [101]
Brushes, battery terminals, commutator, armature, magnets
7 0
2 years ago
Wax, like all matter, comes in many phases. What are the three possible
Levart [38]
A b and c its so simple bro send it 23-89
7 0
2 years ago
A group of college students eager to get to Florida on a spring break drove the 710-mi trip with only minimum stops. They comput
Elis [28]

Answer:

Time taken for trip = 12.74 hour (Approx)

Explanation:

Given:

Distance of trip = 710-mi

Average speed for the trip = 55.7 mi/h

Find:

Time taken for trip = ?

Computation:

⇒ Time = Distance / Speed

⇒ Time taken for trip = Distance of trip / Average speed for the trip

⇒ Time taken for trip = 710-mi / 55.7 mi/h

⇒ Time taken for trip = 12.74 hour (Approx)

7 0
3 years ago
Calculate a pendulum's frequency of oscillation (in Hz) if the pendulum completes one cycle in 0.5 s.
Marina86 [1]
Time taken to complete one oscillation for a pendulum is Time Period, T = 0.5 s 
Frequency of the pendulum oscillation = 1 / Time Period => f = 1 / T = 1 / 0.5  
Frequency f = 2 Hz
3 0
3 years ago
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