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1 answer:
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<u>Answer:</u> The volume of water required is 398 mL
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Mass of solute (manganese (II) nitrate tetrahydrate) = 16 g
Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol
Molarity of solution = 0.16 M
Putting values in above equation, we get:
Hence, the volume of water required is 398 mL
Answer:
Explanation:
Hello!
In this case, since the mole fraction of both gases in the tank is computed via:
It means we need to compute the moles of each gas, just as it is shown down below:
Thus, the mole fractions turn out:
Best regards!