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Sladkaya [172]
3 years ago
6

Thế nào là góc quay xe ?

Engineering
1 answer:
slava [35]3 years ago
8 0

Answer:

what's what is what is it return if you have any clue please let me know Translate in English and send me because most of them are are from English I think so

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A 450 MWt combined cycle plant has a Brayton cycle efficiency of 24% and a Rankine cycle efficiency of 29% with no heat augmenta
Romashka-Z-Leto [24]

Answer:

Output of plant=207.18 MW

Explanation:

Given input energy Q=450 MW

Brayton cycle efficiency\eta_1=24%

Rankine cycle efficiency \eta_2=29%

Combined efficiency for two cycle given as follow

\eta _b=\eta _1+\eta _2-\eta _1\eta _2

\eta _b=0.24+0.29-0.24\times 0.29

\eta_b=0.4604

We know that efficiency \eta =\dfrac{out\ put}{in\ put}

out put of plant=450\times 0.4604

So output of plant=207.18 MW

4 0
3 years ago
The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of t
Tju [1.3M]

Answer:

15.99 ft/s

Explanation:

From Newton's equation of motion, we have

v = u + at

v = Final speed

u = initial speed

a = acceleration

t = time

now

for the points A and C

v = 17.6 ft/s

u = 13.2 ft/s

t = 3 s

thus,

17.6 = 13.2 + a(3)

or

3a = 17.6 - 13.2

3a = 4.4

or

a = 1.467 m/s²

Thus,

For Points A and B

v = speed at B i.e v'

u = 13.2 ft/s

a = 1.467 ft/s²

t = 1.90 s

therefore,

v' = 13.2 + (1.467 × 1.90 )

v' = 13.2  + 2.7867

v' = 15.9867 ≈ 15.99 ft/s

3 0
3 years ago
Which of the following would NOT be
nikdorinn [45]

Answer:

Option A

hands-on assembly of the company's product

Explanation:

The managerial roles mainly include supervision of actual work on a higher level and implementation of organization's policy. The hands-on assembly of company's product is majorly done by junior staff who work under a supervisor who reports to the manager. Therefore, this is not a duty of a manager in a manufacturing field.

7 0
3 years ago
A fluid has a dynamic viscosity of 0.048 Pa.s and a specific gravity of 0.913. For the flow of such a fluid over a flat solid su
sattari [20]

Answer:

Explanation:

First we should recall how Newton's laws relates shear stress to a fluid's velocity profile:

\tau = \mu \cfrac{\partial v}{\partial y}

where tau is the shear stress, mu is viscosity, v is the fluid's velocity and y is the direction perpendicular to flow.

Now, in this case we have a parabolic velocity profile, and also we know that the fluid's velocity is zero at the boundary (no-slip condition) and that the vertex (maximum) is at y=75 \, mm and the velocity at that point is 1.125 \, m/s

We can put that in mathematical terms as:

v(y)= A+ By +Cy^2 \\v(0) = 0\\v(75 \, mm) = 1.125 \, m/s\\v'(75 \, mm) = 0\\

From the no-slip condition, we can deduce that A=0 and so we are left with just two terms:

v(y) = By + C y ^2 \\

We know that the vertex is at y= 75 \, mm and so we can rewrite the last equation as:

v(y) = k(y-75 \, mm) ^2+h

where k and h are constants to be determined. First we check that v( 75 \, mm) = 1.125 \,  m/s :

v( 75 \, mm) = k(75 \, mm -75 \, mm) ^2+h = h = 1.125 \, m/s\\\\h= v_{max} = 1.125 \,  m/s

So we found that h was the maximum velocity for the fluid, now we have to determine k, for that we need to make use of the no-slip condition.

v( 0) = k( -75 \, mm) ^2+  1.125 \,  m/s= 0 \quad (no \, \textendash slip)  \\\\k= - \cfrac{ 1.125 \, m/s }{(75 \, mm ) ^2} = - \cfrac{ 1125 \, mm/s }{(75 \, mm ) ^2}\\\\k= -  \cfrac{0.2}{mm \times s}

And thus we find that the final expression for the fluid's velocity is:

v( y) = 1125-  0.2 ( y -75 ) ^2

where v is in mm/s and y is in mm.

In SI units it would be:

v( y) = 1.125-  200 ( y -0.075 ) ^2

To calculate the shear stress, we need to take the derivative of this expression and multiply by the fluid's viscosity:

\tau = \mu \cfrac{\partial v}{\partial y}

\tau =0.048\,   \cdot  (-400) ( y-0.075   )

for y= 0.050 \, m we have:

\tau =0.048\,   \cdot  (-400) ( 0.050 -0.075   ) = 0.48\, Pa

Which is our final result

5 0
4 years ago
YO CUTIE! HELP MEEEEEE! Hazardous waste is a category that includes all of the following EXCEPT
madam [21]

your answer should be <u>B. Soluble</u>

3 0
3 years ago
Read 2 more answers
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