Answer:
Orbital Time Period is 24 years
Explanation:
This can be explained by the definition of time period.
Time period can be defined as the time taken by an object to complete one cycle, here, time taken to complete one revolution.
Also, we know that an extra solar planet which is also called as an exo planet is that planet which is outside our solar system and orbits any star other than our sun. The system in consideration is extra solar system with a single planet.
Therefore, the time taken by the parent star to move about its mass center is the orbital time period that is 24 years.
Answer:
The air is contained at a high pressure in the tube. When it escapes from a small orifice, it suddenly expands. A large amount of its heat is absorbed in the process of expansion resulting in considerable fall in its temperature. This is why the escaping air feels cold.
Answer:
The girl exerts more pressure.
Explanation:
Pressure can be defined as the force exerted normally or perpendicularly per unit area.
i.e P = F/A
<u>Girls</u>
Area of the heel = 1cm² = 10^(-4) m²
Force = mg = 50 × 10 = 500N
Pressure =


<u>Elephant</u>
<u>Area</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>0</u><u>cm</u><u>²</u><u> </u><u>=</u><u> </u><u>2</u><u>.</u><u>5</u><u> </u><u>x</u><u> </u><u>1</u><u>0</u><u>^</u><u>(</u><u>-</u><u>2</u><u>)</u><u>b</u><u> </u><u>m</u><u>²</u>
<u>Force</u><u> </u><u>=</u><u> </u><u>mg</u><u> </u><u>=</u><u> </u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>N</u>
<u>Pressure</u><u> </u><u>=</u><u> </u>
<u>
</u>
<u>
</u>
Answer:
The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will decrease with time, the surface area between the tire and the road will increase with time, and the net force the tire exerts on the road will be constant with time.
Explanation:
when a wheel has an air leak, it means that the inside of the tire has less air, which means that there will be less air pushing the walls of the tire so that the air pressure decreases.
On the other hand, the tire begins to deform due to lack of air which increases the area of contact with the floor.
As the weight of the car remains constant and the air has a negligible mass the force towards the road will be the same