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erma4kov [3.2K]
4 years ago
6

The magnetic flux through a metal ring varies with time t according to ΦB = 10 at^3 − 5 bt^2, where Φ is in webers, a = 6.00 s^

−3, b = 18.0 s^ -2, and t is in seconds. The resistance of the ring is 5.00 Ω. For the interval from t = 0 to t = 2.00 s, determine the maximum current induced in the ring.
Physics
1 answer:
mixas84 [53]4 years ago
3 0

Answer bruh I really dont know im just trying to set this account

Explanation:

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Convert as indicated step by step 1)1 sec into day 2) 1 week into sec (3) 50cm into meter​
Allushta [10]

Answer:

1) 1,157*10⁻⁵ day; 2) 604800 sec.; 3) 0.5 m.

Explanation:

1) 1 second into one day:

one day consists of 24 hours, it means 24*3600=86400 seconds. Then 1 second is 1/86400 day or 1,157*10⁻⁵ day.

2) 1 week into seconds:

1 day consists of 3600*24=86400 seconds, then the week is 7*86400=604800 seconds.

3) 50 cm into meter:

100 cm is one meter, then 50 cm is 0.5 meter.

PS. note, there is not the only way to perform conversion.

4 0
3 years ago
It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously
Svetlanka [38]

The sound intensity level of 100 physics professors talking simultaneously is equal to 72 decibel.

<u>Given the following data:</u>

  • Sound intensity = 52 dB.

<h3>What is sound intensity?</h3>

Sound intensity can be defined as a measure of the power of a sound wave per unit area. Thus, sound intensity is a quantity that can be used to measure the energy of sound and its unit of measurement is Watts per square meter.

<h3>How to calculate the sound intensity level.</h3>

Mathematically, sound intensity level is given by this formula:

\beta = 10 log(\frac{I}{I_{ref}} )

<u>Note:</u> The reference value of sound intensity is equal to 1.0 \times 10^{-12}\;W/m^2

Thus, the sound intensity for one (1) professor is given by:

I_1 = 1.0 \times 10^{-12} \times 10^{5.2}\\\\I_1=1.585 \times 10^{-7}\;W/m^2

For 100 professors, the sound intensity is:

I_{100} = 1.585 \times 10^{-7} \times 100\\\\I_{100}=1.585 \times 10^{-5}\;W/m^2

Substituting the parameters into the formula, we have;

\beta = 10 log(\frac{1.585 \times 10^{-5}}{1.0 \times 10^{-12}})\\\\\beta = 10 log(15.58 \times 10^{6})\\\\\beta = 10 \times 7.2\\\\\beta =72\;dB

Read more on sound intensity here: brainly.com/question/17062836

<u>Complete Question:</u>

One physics professor talking produces a sound intensity level of 52 dB. It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?

7 0
2 years ago
What is an atomic nucleus
Agata [3.3K]

Answer:

The atomic nucleus is the small, dense region consisting of protons and [[]]s at the center of an atom

Explanation:

8 0
3 years ago
Read 2 more answers
How was the earliest version of the periodic table organized before Mendeleev?
astraxan [27]
This is how the periodic table is organized.

Hope this helps!

7 0
3 years ago
A 2.0 kg mass weighs 10 Newtons on planet X. what is the acceleration due to gravity on planet X? Show the work.
KengaRu [80]

Answer: The gravitational acceleration on planet X is 5 N/kg

On Earth (with the gravitational accelartion g_E) the mass of 2kg will correspond to

F_E = m\cdot g_E = 2.0 \mbox{kg}\cdot 9.8 \frac{N}{kg} = 19.6 N

On planet X we are told the same measure is only 10N. Since there is a proportional relationship between g and F, we can calculate g_X:

\frac{F_E}{g_E}=\frac{F_X}{g_X} \implies\\g_x = \frac{g_E\cdot F_X}{F_E}=\frac{9.8 N/kg \cdot 10 N }{19.6N}=5 \frac{N}{kg}

8 0
3 years ago
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