A 2.5 m tall steel cylinder has a cross sectional area of 1.5 mA 2 EA. At the bottom with a height of 0.5 m is liquid water and
on top of which is a 1 m high layer of gasoline (rhogasoline= 925kg/m3 ). The gasoline surface is exposed to atmospheric air at 101 kPa. Sketch the arrangement. Where is the pressure highest in the water (indicate in the sketch), and what is the value of the absolute pressure?
1 answer:
Answer:
124 kPa
Explanation:
The highest pressure in the water is in the bottom of the cylinder. The reason is because all the weight of the water and the gasoline puts some pressure plus the atmospheric air. So, the absolute pressure would be the one exerted by the atmosphere, the gasoline and the water and is calculated as follows:
≈124 kPa
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Answer:
I = 0.11 A
Explanation:
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- The current flowing through the cell-phone circuitry is 0.11 A.
Answer:
E=-1.51 eV.
Explanation:
The nth level energy of a hydrogen atom is defined by the formula,
Given in the question, the hydrogen atom is in the 3p state.
Then energy of n=3 state is,
Therefore, energy of the hydrogen atom in the 3p state is -1.51 eV.
Now, the value of L can be calculated as,
For 3p state, l=1
Therefore, the value of L of a hydrogen atom in 3p state is .
1)
The force of gravitation between the two objects is given by:
where
is the gravitational constant
m1 = 20,000 kg is the mass of the first object
m2 = 12,500 kg is the mass of the second object
r = 5 m is the distance between the two objects
Substituting the numbers inside the equation, we find
2)
From the formula in exercise 1), we see that the force is inversely proportional to the square of the distance:
this means that if we cut in a half the distance without changing the masses, the magnitude of the forces changes by a factor
So, the gravitational force increases by a factor 4. Therefore, the new force will be
3) 12.5 Nm
The torque is equal to the product between the magnitude of the perpendicular force and the distance between the point of application of the force and the centre of rotation:
Where, in this case:
F = 25 N is the perpendicular force
d = 0.5 m is the distance between the force and the center
By using the equation, we find
4) 0.049 kg m^2/s
The relationship between angular momentum (L), moment of inertia (I) and angular velocity () is:
In this problem, we have
So, the angular momentum is