Answer:
so pressure in A must be one third the pressure in B
Explanation:
We shall apply gas law to the cylinders A and B . Since their quantity are same so their no of mole will also be same .
For cylinder A
Temperature T , volume 3V , pressure P₁ , no of mole = n
so
P₁ X 3V = n R T
For cylinder B
Temperature T , volume V , pressure P₂ ,no of mole = n
so
P₂ X V = n R T
From the two equation above
P₁ X 3V = P₂ X V

P₁ = P₂ / 3
so pressure in A must be one third the pressure in B
Answer:
The 50-W bulb glows more brightly than the 100-W bulb
Explanation:
The bulb has a rating of 100 W under 110 V . So it will glow with full brightness when it is fed 110 V . When bulbs are in parallel combination , each bulb receives 110 V . So they glow with full brightness .
When they are in series combination , 110 supply voltage gets distributed between the , thus , reducing the voltage appearing on each of them less than 110 V . So their brightness is reduced.
resistance = V
Bulb having high wattage rating has low resistance resulting in higher current . In the second case , both have same current as they are in series combination . So more heat will be generated in bulb having more resistance . Since 50 W bulb has higher resistance , it will glow brighter than 100 W bulb.
Answer:
8.67×10⁻⁶ N/m²
Explanation:
p = Momentum of a photon
E = Energy of a photon
c = Speed of light
I = Intensity of light
Force = dp/dt


As given in question

Now F/A = Pressure

∴ Magnitude of the pressure on the sail is 8.67×10⁻⁶ N/m²
The answer is F=3.906 x 10^-9