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kkurt [141]
4 years ago
11

A wave has a period of 2 seconds and a wavelength of 4 meters calculate its frequency and speed

Physics
1 answer:
Harlamova29_29 [7]4 years ago
5 0
-- Frequency = 1/period = 1/2sec = 1/2 per sec = <em>1/2 Hz</em>.

-- Speed = (wavelength) x (frequency) = (4 m) x (1/2 per second) = <em>2 m/sec</em>
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Which statements are true about the flow of blood in the body? Check all that apply.
Trava [24]

Answer:

i need some explanation

Explanation:

4 0
4 years ago
8. Ella wants to replace old bulbs of her home with new LED bulbs. She buys LED bulb that has inbuilt AC to DC converter of outp
tankabanditka [31]

The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

  • Electrical power = voltage × current

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

  • Work done = power × time (in seconds)

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Learn more about electrical power and work done at: brainly.com/question/23901751

#SP1

3 0
2 years ago
What is the magnitude of the force required to stretch a 20 cm-long spring, with a spring constant of 100 N/m, to a length of 21
GalinKa [24]

The correct answer to the question is: 1 N.

EXPLANATION:

As per the question, the spring constant or the force constant of the spring is given as k = 100 N/m.

The original length of the spring L = 20 cm.

The stretched length of the spring L'= 21 cm.

Hence, the change in length will be-

                              ∆L = L' - L

                                    = 21 cm - 20 cm

                                    = 1 cm

                                    = 0.01 m

We are asked to calculate the magnitude of force acting on the spring .

From Hooke's  law, we know that the restoring force that acts on the spring is proportional to the distance .

Mathematically it can be written as -

                F = - kx.

Here, k is the force constant.

         x is the change in length due to compression or elongation.

The negative sign is due to the fact that it is opposite to the applied force.


Hence, the applied force on the spring is calculated as -

            F = kx

               = k × ∆L

               = 100 N/ m × 0.01 m

               = 1 N.

Hence, the force acting on the spring is 1 N.


                                                   

8 0
3 years ago
Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
svlad2 [7]

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

W=F\times s

W=Fs\ cos\theta

\theta is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, \theta=30

Work done is given by :

W=Fs\ cos\theta

W=30\times 160\ cos(30)

W = 4156.92 Joules

So, the work done by the object is 4156.92 Joules. Hence, this is the required solution.

5 0
3 years ago
Give the atomic mass and atomic number of this atom.
Soloha48 [4]
I think it would be sodium.

Because the atomic mass is protons + neutrons, so I did 6 + 5 = 11
Then I looked on the periodic table for an element with the atomic mass of 11 and it was Na... Sodium.
4 0
3 years ago
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