A metallic bond is a force that holds atoms together in a metallic substance.
One aluminum atom will cost 0.84 × 10⁻²³ cents.
Explanation:
Aluminium costs 85 cents per 453.592 grams.
number of moles = mass / atomic weight
number of moles of aluminium = 453.592 / 27 = 16.8 moles
To calculate the number of aluminum atoms we use the Avogadro's number:
if 1 mole of aluminum contains 6.022 × 10²³ aluminum atoms
then 16.8 moles of aluminum contains X aluminum atoms
X = (16.8 × 6.022 × 10²³) / 1 = 101.17 × 10²³ aluminum atoms
Now, taking in account the aluminium price, we devise the following reasoning:
if 101.17 × 10²³ aluminum atoms costs 85 cents
then 1 aluminum atom costs Y cents
Y = (1 × 85) / (101.17 × 10²³) = 0.84 × 10⁻²³ cents
Learn more about:
Avogadro's number
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Strontium has an electron configuration of [Kr]5s²
<h3>Further explanation </h3>
In an atom there are levels of energy in the shell and sub shell
This energy level is expressed in the form of electron configurations.
Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f. The maximum number of electrons for each sub shell is
s: 2 electrons
p: 6 electrons
d: 10 electrons and
f: 14 electrons
From an electron configuration of [Kr]5s² can be concluded :
- element is in period 5 (5 = shell)
- element is group 2(valence electron =2 and block s)
- has atomic number 38 (Kr = 36 + 2(valence elektron from 5s²)
If we look at the periodic system, the elements that meet the requirements in question are Strontium (Sr)
<em>réponse</em>: <em>verdadero</em>
<em>Explication</em>:
Answer:
24 g of carbon
Explanation:
Methane is produced by this reaction:
C(s) + 2H₂(g) → CH₄ (g)
At STP 1 mol of any gas is contained at 22.4L. Let's see how many moles are contained at 44.8L
(1L = 1dm³)
44.8 L . 1mol / 22.4L = 2 moles
Stoichiometry at reaction is 1:1.
1 mol of methane is produced by 1 mol of carbon.
In conclussion, 2 moles of gas may come from 2 moles of C.
We determine the mass:
2 mol . 12 g /mol = 24 g
