Explanation:
Molar mass of 
= 39.1 + 35.5 + 3(16.0) = 122.6 g
Molar mass of KCl = 39.1 + 35.5 = 74.6 g
Molar mass of 
= 32.0 g
According to the equation, 2 moles of reacts to give 3 moles of oxygen.
Therefore, 2 (122.6) = 245.2 g of will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of gives 96.0 g of oxygen.
(a) Calculate the amount of oxygen given by 2.72 g of as follows.
of
(b) Calculate the amount of oxygen given by 0.361 g of as follows.
of
c) Calculate the amount of oxygen given by 83.6 kg as follows.
of
Convert kg into grams as follows.
= 32731 g of
(d) Calculate the amount of oxygen given by 22.5 mg of as follows.
Convert mg into grams as follows.
of
answer:
IMAGE IS SUPER UNCLEAR SORRY LUV <3
explanation:
your phone must me from 2009 with that trash camera quality sweetie i suggest you get a new one... oh wait you can't you're broke :(
Answer: 1. 
moles
2. 90 mg
Explanation:
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 
moles of ozone is removed by =
moles of sodium iodide.
Thus moles of sodium iodide are needed to remove 
moles of 
2. 
According to stoichiometry:
1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 0.0003 moles of ozone is removed by =
moles of sodium iodide.
Mass of sodium iodide= 
(1g=1000mg)
Thus 90 mg of sodium iodide are needed to remove 13.31 mg of .
Answer:
2Ba₃(PO₄)₂ +6SiO₂ ⇒ P₄O₁₀ +6BaSiO₃
Explanation:
Equating coefficients, you get ...
aBa₃(PO₄)₂ +bSiO₂ ⇒ cP₄O₁₀ +dBaSiO₃
For Ba: 3a = d
For P: 2a = 4c
For O: 8a +2b = 10c +3d
For Si: b = d
__
Expressing everything in terms of b and c, we get ...
d = b
a = b/3 = 2c
From the second, b = 6c, so we have ...
a = 2c
b = 6c
c = c
d = 6c
And we can write the equation with c=1 as ...
2Ba₃(PO₄)₂ +6SiO₂ ⇒ P₄O₁₀ +6BaSiO₃
Answer:
6.9 (two sig figs)
Explanation:
2.375 + 4.5 = 6.875 = 6.9
When adding or subtracting, sig figs are determined by the least number of digits past the decimal point.
