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dlinn [17]
3 years ago
8

PLEASE HELP ALL OTHER ANSWERS ON BRAINLY ARE INCORRECT AS THEY ARE ALL THE SAME HELP!!! WILL MARK BRAINLIEST!!! Give the quantum

number set for one electron in the 2p sublevel of a nitrogen (N) atom. (3 points)
Chemistry
1 answer:
stealth61 [152]3 years ago
6 0

it can form 3 bonds because 1 electron is in each of the 3 2p oribitals.

The electron configuration of nitrogen (atomic number 7) is 1s2 2s2 2px1 2py1 2pz1

so specifically the 2p oribital is :

2px1 2py1 2pz1

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How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?
mash [69]

Answer : Both solutions contain 3.011 X 10^{23} molecules.

Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain 3.011 x 10^{23} molecules.

Avogadro's Number is  N_{A} =  6.022 X 10^{23} which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.

Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.

Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.

Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.

We can calculate the number of molecules for each;

Number of molecules  = N_{A} X M;

∴  Number of molecules =  6.022 X 10^{23} X 0.5 mol/L X 1 L which will be  = 3.011 X 10^{23}

Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.

7 0
2 years ago
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Changing a solid to a liquid to a gas is changing the<br> matter.<br> *<br> Your answer
sukhopar [10]

Answer:

i could help you can you explain more plzzzzzz i really need points

Explanation:

6 0
2 years ago
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How many neutrons are found in a stable isotope of uranium-235?
bezimeni [28]

thx but it's actually 143

8 0
3 years ago
A gas mixture contains HBr, NO2, and C2H6 at STP.If a tiny hole is made in the container, which gas will effuse fastest?Which ga
MakcuM [25]

Explanation:

Molar mass of HBr = 81 g/mol

Molar mass of nitrogen dioxide gas = 46 g/mol

Molar mass of ethane = 30 g/mol

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So, the gas with least molar mass will effuse out fastest from the container and that is ethane gas.

The formula for average kinetic energy is:

K.E=\frac{3}{2}kT

where,

k = Boltzmann’s constant = 1.38\times 10^{-23}J/K

T = temperature = 273.15 K ( at STP)

As we can see from the formula that kinetic energy depends upon only temperature of the gas molecule.

So, from this we can say that all the gas molecules have the same average kinetic energy at this temperature.

5 0
3 years ago
When 7.80 mL of 0.500 M AgNO3 is added to 6.25 mL of 0.300 M NH4Cl, how many grams of AgCl are formed?
irina1246 [14]

Answer:

The answer to your question is 0.269 grams of AgCl

Explanation:

Data

[AgNO₃] = 0.50 M

Vol AgNO₃ = 7.80 ml

[NH₄Cl] = 0.30 M

Vol NH₄Cl = 6.25 ml

mass of AgCL

Balanced reaction

                 AgNO₃(aq)  +  NH₄Cl(aq)   ⇒   AgCl (s) + NH₄NO₃ (aq)

Process

1.- Calculate the moles of AgNO₃

Molarity = moles / volume

moles = Molarity x volume

moles = 0.50 x 0.0078

moles = 0.0039

2.- Calculate the moles of NH₄Cl

moles = 0.30 x 0.0063

moles = 0.00188

3.- Calculate the limiting reactant

The proportion of     AgNO₃(aq)  to  NH₄Cl(aq) is 1 :1, then, we conclude that the limiting reactant is NH₄Cl(aq), because there are less amount of this reactant in the experiment.

4.- Calculate the moles of AgCl

                     1 mol of NH₄Cl  ---------------- 1 mol of AgCl

              0.00188 mol of NH₄Cl ------------- x

                     x = (0.00188 x 1) /1

                     x = 0.00188 moles of AgCl

5.- Calculate the grams of AgCl

molecular mass of AgCl = 108 + 35.5 = 143.5 g

                         143.5 grams of AgCl -------------- 1 mol

                         x -------------------------------------------0.00188 moles of AgCl

                          x = (0.00188 x 143.5) / 1

                          x = 0.269 grams of AgCl

8 0
3 years ago
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