The mass of pentane the student should weigh out is
The density of pentane is 0.626 gcm-3
To calculate the mass of pentane following expression is used,
(Density is defined as the mass divide by volume)
Density = mass / volume
mass of pentane = Density of pentane * Volume of pentane
mass of pentane = 0.626 gcm-3 * 45.0 mL
= 28.17 g
Here the unit of mass of pentane is g,
However the unit of density is gcm-3 and unit of volume is mL i.e. cm3
Hence, Mass = gcm-3 * cm3
Mass = g
The mass of pentane the student should weigh out is 28.17g
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Electrons: negative
Protons: positive
Neutrons: nuetral
Answer:
Explanation:
MW of NaOH = 40 g/mol
MW of KCl = 74.55 g/mp;
250 mL = .25 L
100g NaOH / 40 g = 25 mol
100g KCl/ 74.55g = 1.34 mol
Molarity of NaOH: 25/.25 = 100M
Molarity of KCl: 1.34/.25 = 5.36 M
The volume of a block of lead metal that has a density of 11.3g/mL and weighs 2.10g is 0.186mL.
<h3>How to calculate volume?</h3>
The volume of a substance can be calculated by dividing the mass of the substance by its density. That is;
Volume = mass ÷ density
According to this question, a chemist has a block of lead metal (density is 11.3 g/mL). The block weighs 2.10g.
Volume = 2.10g ÷ 11.3g/mL
Volume = 0.186mL
Therefore, the volume of a block of lead metal that has a density of 11.3g/mL and weighs 2.10g is 0.186mL.
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