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rodikova [14]
3 years ago
7

Amy needs 5.0 V for some integrated circuit experiments. She uses a 9.0 V battery and two resistors to make a voltage divider. O

ne resistor is 310 . She decides to make the other resistor smaller. What value should it have

Physics
1 answer:
just olya [345]3 years ago
7 0

Answer:

The value of smaller resistor is 248 Ω.

Explanation:

Voltage divider circuit is used to convert a higher voltage to a smaller voltage with the help of resistors which are connected in parallel.

As shown in the circuit, Vs is the source voltage, R₁ and R₂ are the two resistors and V₀ is the output voltage.

Applying KVL in the circuit, the output voltage is given by :

V_{0} = \frac{V_{s}R_{2}  }{R_{1} +  R_{2}  }

According to the problem, R₂ = 310Ω , V₀ = 5 V and Vs = 9 V. Substitute these values in the above equation.

5 = \frac{9\times310  }{R_{1} +  310  }

R_{1}+310 = \frac{9\times310}{5}

R_{1} = 558 - 310

R₁ = 248Ω

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