Answer:
60°
Explanation:
It will be equilateral triangle, you can prove with the cosine theorem.
1)P^2=P^2+P^2 - 2×P×P× cos A
2) cos A= P^2 / 2× P^2 = 1/2
cos A = 1/2
A = 60°
If you wrote this question right,it will be solved like this :)
Answer:
relative vorticity is -0.868 ×
s-1
Explanation:
given data
air parcel at latitude = 18◦N
relative vorticity = 5.8 × 10^−5 s−1
to find out
relative vorticity
solution
we will apply here conservation of vorticity that is
ζ + f = constant
we know ζ initial = 2Ωsin(5π/18)
and f initial = 5.8 ×
and f final = 2Ωsin(π/18)
and here angular frequency Ω = 0.7272 ×
s-1
its mean
ζ initial - ζ final = f final - f initial
so
ζ final = ζ initial - f final + f initial
ζ final = - 2Ωsin(5π/18) + ( 2Ωsin(π/18) + 5.8 ×
)
ζ final = - 2(0.7272 ×
) sin(5π/18) + ( 2(0.7272 ×
)sin(π/18) + 5.8 ×
)
ζ final = -0.868 ×
s-1
so relative vorticity is -0.868 ×
s-1
Answer:
Spontaneous emission is a quantum effect, which in a semiclassical picture can be described as an emission which is stimulated by vacuum noise.
Answer:
In expanded notation the answer is 100,70 5
Explanation:
Hope this helps
A pair of scissors .....................................