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saw5 [17]
3 years ago
9

A sample with a molar mass of 34.00 g/mol is found to consist of 5.9783% Hydrogen and 94.0217% oxygen. Find it’s molecular formu

la.
Chemistry
1 answer:
kozerog [31]3 years ago
5 0

Answer:

The formula is H202 (hydrogen peroxide, known as hydrogen peroxide)

Explanation:

100%----34g

5, 9783%---X= (5, 9783%x 34g)/100% =2 g

1g---1 atom of H

2g----x= 2g x 1 atom of H/1g = 2 atom of H

100%----34g

94, 0217%---X= (94,0217%x 34g)/100% =32 g

16g---1 atom of 0

32g----x= 32g x 1 atom of 0/16g = 2 atom of 0

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frozen [14]

Answer:

1.79x10^-14

Explanation:

pOH + pH = 14

H+=10^-pH

- Hope that helps! Please let me know if you need further explanation.

3 0
3 years ago
A ball was kicked by a player, the ball was stationary, then it gains a velocity of 5 m/s North. Did the ball accelerate or no?
Tomtit [17]

Answer:

yes

Explanation:

it started moving North 5 m/s

7 0
3 years ago
What type of electrical charge does the electron carry? a. positive
vivado [14]
The type of charge an electron carries is B negative
3 0
2 years ago
Read 2 more answers
Chlorine monoxide accumulates in the stratosphere above Antarctica each winter and plays a key role in the formation of the ozon
Ahat [919]

The question is incomplete, the complete question is;

Chlorine monoxide accumulates in the stratosphere above Antarctica each winter 3nd plays a key role the formation of the ozone hole above the South Pole each spring Eventually. CIO decomposes acco to the equation: 2CIO(g) rightarrow CL2(g) + O2(g) The second-order rate constant for the decomposition of CIO is 6950000000 M-1 s-1 at a particular temperature Determine the half-life of CIO when its initial concentration is .0000000185 M

Answer:

7.8 * 10^-3 s

Explanation:

Given that the half life of a second order reaction is obtained from the formula;

t1/2 = k-1[A]o-1

t1/2 = 1/k[A]o

second order rate constant (k) = 6950000000 M-1 s-1

initial concentration ([A]o) =0.0000000185 M

t1/2 = 1/6950000000 * 0.0000000185

t1/2 = 7.8 * 10^-3 s

7 0
3 years ago
I need help on this someone please help
Murljashka [212]

1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?

Answer:

v = 0.94 mL

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Given data:

Density of soap =  1.06 g/mL.

Mass  = 1 g

Volume = ?

Solution:

d = m/v

v = m/d

v = 1 g/1.06 g/mL

v = 0.94 mL

2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?

Answer:

m = 1370 g

Given data:

Density of soap =  1.37 g/mL.

Mass  = ?

Volume = 1.0 L ( 1000 mL)

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

m = d × v

m = 1.37 g/mL  ×  1000 mL

m = 1370 g

3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?

Answer:

v = 29.2 mL

Given data:

Density of soap =  0.754 g/mL.

Mass  = 22 g

Volume = ?

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

v = m/d

v = 22 g/0.754 g/mL

v = 29.2 mL

6 0
3 years ago
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