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padilas [110]
4 years ago
12

A mixture contains 0.5 mol He, 0.09 mol CO2, 0.75 mol O2 and 1.5 mol At. Which gas has the highest partial pressure ?

Chemistry
1 answer:
Volgvan4 years ago
7 0

Answer:

  • <u><em>At.</em></u>

Explanation:

The <em>partial pressure</em> of a gas in a mixture is equal to the mole fraction of the gas multipplied by the total pressure.

The mole fraction of a component in a mixture is equal to the number of moles of the component divided by the total number of moles in the mixture.

In the mixture given there are:

  • 0.5 mol He,
  • 0.09 mol CO₂,
  • 0.75 mol O₂, and
  • 1.5 mol At.

Hence, the gas with greatest number of moles, and, consequetly, greatest mole fraction and<em> highest partial pressure</em> is<em> At</em>.

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A scuba diver knows that she needs 50.0mol of air for an upcoming dive. What size (volume) tank will she need to fill for this d
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Answer:

1120 L.

Explanation:

Hello!

In this case, as no conditions of pressure of temperature are given for this problem, we can assume that the scuba diver dives at STP (1 atm and 273.15 K), which means that 1 mole of air would occupy a volume of 22.4 L.

In such a way, since she needs 50.0 moles of air, the following ratio is useful to compute the size (volume) of the tank she needs:

V_2=\frac{V_1*n_2}{n_1}

Thereby, we plug in to obtain:

V_2=\frac{22.4L*50.0mol}{1mol}\\\\V_2=1120 L

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3 years ago
The mole ratio of two reactants in a chemical equation is determined by
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Answer:

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You have 4 moles of oxygen gas in a flask. 4 moles of helium gas is added. What happens to the total pressure of the gases in th
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Answer: The correct option is (c). The total pressure doubles.

Solution:

Initially,  only 4 moles of oxygen gas were present in the flask.

p_{O_2}=Tp_1\times X_{O_2}  (X_{O_2}=\frac{4}{4}) ( according to Dalton's law of partial pressure)

p_{O_2}=Tp_1\times 1=Tp_1....(1)

Tp_1= Total pressure when only oxygen gas was present.

Final total pressure when 4 moles of helium gas were added:

X'_{O_2}=\frac{4}{8}=\farc{1}{2},X_{He}=\frac{4}{8}=\frac{1}{2}

partial pressure of oxygen in the mixture :

Since, the number of moles of oxygen remains the same, the partial pressure of oxygen will also remain the same in the mixture.

p_{O_2}=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

Tp_2= Total pressure of the mixture.

from (1)

Tp_1=Tp_2\times X'_{O_2}=Tp_2\times \frac{1}{2}

On rearranging, we get:

Tp_2=2\times Tp_1

The new total pressure will be twice of initial total pressure.

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