Hello!
1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?
- <u><em>We have the following data:</em></u>
Vo (initial volume) = 1.00 L
V (final volume) = 473 mL → 0.473 L
Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)
P (final pressure) = ? (in atm)
- <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>
![P_0*V_0 = P*V](https://tex.z-dn.net/?f=P_0%2AV_0%20%3D%20P%2AV)
![1*1 = P*0.473](https://tex.z-dn.net/?f=1%2A1%20%3D%20P%2A0.473)
![1 = 0.473\:P](https://tex.z-dn.net/?f=1%20%3D%200.473%5C%3AP)
![0.473\:P = 1](https://tex.z-dn.net/?f=0.473%5C%3AP%20%3D%201)
![P = \dfrac{1}{0.473}](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%7B1%7D%7B0.473%7D)
![\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7BP%20%5Capprox%202.11%5C%3Aatm%7D%7D%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5Cbf%5Cgreen%7B%5Ccheckmark%7D)
<u><em>Answer: </em></u>
<u><em>The new pressure of the gas is 2.11 atm </em></u>
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![\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}](https://tex.z-dn.net/?f=%5Cbf%5Cblue%7BI%5C%3AHope%5C%3Athis%5C%3Ahelps%2C%5C%3Agreetings%20...%5C%3ADexteright02%21%7D%5C%3A%5C%3A%5Cddot%7B%5Csmile%7D)
Answer:
more electron deficient
Explanation:
The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.
This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.
Hence, the nitro group makes the pyrinde ring more electron deficient
I believe the answer is A the 1st one
0.00011811023622 <span>i</span><span>nches</span>
Answer: let me figure it out rlly quick
Explanation: