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Chemistry

1 answer:

Andreyy893 years ago

8 0

Answer:

The answer is B

Explanation:

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A container holds 6.4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.24

Degger [83]

The partial pressure of hydrogen is 0.31 atm

calculation

find the number of hydrogen moles the container, that is

25/100 x 6.4 =1.6 moles of hydrogen

find the partial pressure for hydrogen in 1.6 moles

that is 6.4 moles= 1.24 atm
1.6 moles= ?

by cross multiplication

1.6moles x1.24 atm/ 6.4 moles= 0.31 atm

6 0

3 years ago

Which situation is the best analogy for the doppler effect?

Phoenix [80]

If you want an example then a car passing by a standing man is the best one !!

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3 years ago

Read 2 more answers

Michelle is trying to find the average atomic mass of a sample of an unknown

GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

Abundance of isotope A (A%) = 59.34%
Mass of isotope A = 113.6459 amu
Mass of isotope B = 115.8488 amu
Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

$Average \: atomic \: mass \: = \frac{mass \: of \: A \times A\%}{100} + \frac{mass \: of \: B \times B\%}{100} \\ \\ Average \: atomic \: mass \: = \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\ \\ Average \: atomic \: mass \: = 114.54 \: amu \\ \\$

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0

2 years ago

A scientist is unsure about the accuracy of her experiment. She has checked her equipment and found it to be in good working ord

polet [3.4K]

Answer:

Explanation:

The correct thing to do in this case would be to repeat the experiment.

The scientist would need to repeat the experiment in order to double-check the accuracy. If the accuracy is indeed doubtful, he/she can be able to trace the source of the error by repeating the experiment.

The correct option is D.

8 0

3 years ago

What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point

Darya [45]

Answer: The amount of energy absorbed by water is 5390 Calories

Explanation:

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

$q=m\times L_{vap}$