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Natalija [7]
3 years ago
12

A hydrogen fuel cell is more efficient than a combustion reaction because very little of the released energy is released as ___.

When used at home, a fuel cell eliminates the need for___
1) A. Heat
B. Electrical energy
C. Chemical energy

2) A. Oxygen
B. Hydrogen
C. An electrical grid
Chemistry
2 answers:
Studentka2010 [4]3 years ago
8 0
It would be A. heat and C. an electric grid.

Hope This Helps You!
Good Luck Studying :)
Klio2033 [76]3 years ago
7 0
A hydrogen fuel cell is more efficient than a combustion reaction because very little of the released energy is released as "Heat". <span>When used at home, a fuel cell eliminates the need for "An Electrical grid"

Hope this helps!</span>
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in Analytical chemistry laboratory. Nickle(ppm)in water sample estimated by two different students was as ,student 1 (25 24 24 2
frosja888 [35]

Answer:

Answers are in the explanation

Explanation:

Precision and accuracy are both statistical concepts. Precision is about how close are the measured values to each other. Accuracy is closeness of the measured values to a specific value or reference value.

There are many ways to calculate precision and accuracy, one is stimating precision as <em>Relative Uncertainty </em>and accuracy as <em>Relative Error.</em>

Formulas are:

Relative Uncertainty: Standard desviation /  Measured value.

Relative Error: Measured Value - Expected Value / Expected value

<em>Measured value is the aveage of the values.</em>

<em />

For student 1:

Mean = 25

Standard desviation = 1.5275

Relative Uncertainty: 1.5275 /  25

Relative Uncertainty: 0.061

Relative Error: 25 - 20 / 20

Relative Error: 0.25

For student 2:

Mean = 24.5

Standard desviation = 0.5477

Relative Uncertainty: 0.5477 / 24.5

Relative Uncertainty: 0.02

Relative Error: 24.5 - 20 / 20

Relative Error: 0.225

<em>As the student 2 has a low Relative error and uncertainty, you can say student 2 is more accurate and precise</em>

6 0
3 years ago
Can someone explain to me how to do Stoichiometry problems please
mars1129 [50]

Answer:

where is the problem

Explanation:

i have no clue

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=I_%7B2%7D" id="TexFormula1" title="I_{2}" alt="I_{2}" align="absmiddle" class="latex-formula">
gogolik [260]

Answer: I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

Explanation:

An Oxidant is any substance that oxidizes, or receives electrons from, another; in so doing, it becomes reduced in oxidation number.

A Reductant thus exactly the opposite.

Note that the equation provided shows that Iodine (I2) received an electron to become NEGATIVELY CHARGED:

I2 --> 2I-.

The oxidation number reduced from 0 to -1.

In contrast, the oxidation number of 2S2O3(-2) increases from -4 to -2.

Thus, I2 is the Oxidant; while the 2S2O3(-2) is the reductant.

7 0
3 years ago
2. Which of the following elements does not lose an electron easily? (a) Na (6) F (c) Mg (d) Al​
vaieri [72.5K]

Answer:

Answer: (b) F

Explanation:

Sodium has 1, magnesium has 2 and Aluminium has 3 electrons in its outermost shell whereas Fluorine has 7 electrons in its outermost shell hence Fluorine does not lose electrons easily.

The electronic configuration of fluorine is 2,7.

Fluorine is the ninth element with a total of 9 electrons.

The first two electrons will go in the 1s orbital.

The next 2 electrons for F go in the 2s orbital.

The remaining five electrons will go in the 2p orbital. Therefore the F electron configuration will be 1s22s22p5.

3 0
2 years ago
Please help Asap………………
vladimir2022 [97]

Answer:

3rd

Explanation:

6 0
3 years ago
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