Gravitational Potential energy is the energy stored with regard to position.
the equation for potential energy is as follows
P.E = mass x gravitational acceleration x height from the ground
gravitational acceleration - 9.8 ms⁻²
substituting the values in the equation
P.E = 125 kg x 9.8 ms⁻² x 1500 m
P.E = 1 837 500 J
therefore the potential energy of the diver at 1500 m high is 1 837 kJ
To solve this problem it is necessary to apply the concepts related to the energy released through the mass defect.
Mass defect can be understood as the difference between the mass of an isotope and its mass number, representing binding energy.
According to the information given we have that the reaction presented is as follows:
The values of the atomic masses would then be:
Th = 232.037146 u
Ra = 228.028731 u
He = 4.0026
The mass difference of the reaction would then be represented as
From the international measurement system we know that 1 atomic mass unit is equivalent to 931.5 MeV,
Therefore the energy is 5.414MeV
Answer:
please the answer below
Explanation:
(a) If we assume that our origin of coordinates is at the position of charge q1, we have that the potential in both points is
k=8.89*10^9
For both cases we have
(b) by replacing this values of r in the expression for V we obtain
hope this helps!!
Answer:
In the surface of the moon, gravitational acceleration is 1.63 m/s*2.
Explanation:
An object of mass M will accelerate gravitationally at a distance R if it is at the following distance:
g = G*M/R^2
Where the gravitational constant is G.
G = 6.67*10^(-11) m^3/(kg*s^2)
At the surface of a moon, the distance between its surface and its center will be equal to its radius, since a moon's mass is concentrated at its center, thus:
R = 1740 km
It's important to remember that we need meters in order to work:
1 km = 1000 m
so:
1740 km = (1740)*1000 m = 1740000 m
R = 1740000 m
Basically, the mass consists of:
M = 7.4x10^22 kg
Incorporating all that into the gravitational acceleration equation, we get:
g = (6.67*10^(-11) m^3 / (kg*s^2))*(7.4x10^22 kg) / ( 1740000 m)^2
g = 1.63 m / s^2
In the surface of the moon, gravitational acceleration is 1.63 m / s*2.
