Fundamental frequency, f₀ = 84 Hz
Second harmonic is 2f₀ = 2* 84 Hz = 168 Hz
Answer:
200.0 g of A, and 21.00 g of B.
Explanation:
Let's call the grams of food A as x and the grams of food B as y, so the units of niacin and retinol in food A are the units per gram multiplied by the mass:
Niacin: 0.22x, Retinol: 170x
And in food B:
Niacin: 0.40y, Retinol: 95y
The total unitis of niacin is 52.4 and of retinol is 35995, thus:
0.22x + 0.40y = 52.4
170x + 95y = 35995
Let's multiply the first equation by -772.7, and sum with the second one:
-170x - 309y = -40490
170x + 95y = 35995
---------------------------------------
-214y = -4495
y = 21.00 g of B
Thus,
0.22x + 0.40*21.00 = 52.4
0.22x = 44
x = 200.0 g of A
Explanation:
At 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
What is an ideal gas equation?
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide
the given mass by the number of moles to get molar mass.
Given data:
P= 0.0721 atm
n=\frac{mass}{molar \;mass}n=
molarmass
mass
R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}R=0.082057338LatmK
−1
mol
−1
T=?
Putting value in the given equation:
\frac{PV}{RT}=n
RT
PV
=n
density = \frac{2 \;atm\; X molar\; mass}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}density=
0.082057338LatmK
−1
mol
−1
XT
2atmXmolarmass
0.260 g/L = \frac{0.0721 \;atm\; X 108.07 g/mol}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}0.260g/L=
0.082057338LatmK
−1
mol
−1
XT
0.0721atmX108.07g/mol
T = 365.2158727 K= 365 K
Hence , at 365 K temperature sulfur tetrafluoride have a density of 0.260 g/L at 0.0721 atm.
Answer:
There are two phase changes where the heat energy is released: Condensation: When gas condenses to liquid the quantity of energy converted from chemical to heat is called the Heat of Vaporization or Δ Hvap .
The condition of free vaporisation throughout the liquid is called
- <em>(</em><em>4</em><em>)</em><em> </em><em>Boiling</em><em> </em>
<u>We</u><u> </u><u>can</u><u> </u><u>also</u><u> </u><u>define</u><u> </u><u>it</u><u> </u><u>as</u><u> </u><u>Free</u><u> </u><u>vaporisation</u><u> </u><u>throughout</u><u> </u><u>the</u><u> </u><u>liquid</u><u> </u><u>is</u><u> </u><u>called</u><u> </u><u>boiling</u><u>,</u><u> </u><u>basically</u><u> </u><u>its</u><u> </u><u>the</u><u> </u><u>definition</u><u> </u><u>of</u><u> </u><u>boiling</u><u>.</u><u> </u>
<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><u>The</u><u> </u><u>temperature</u><u> </u><u>at</u><u> </u><u>which</u><u> </u><u>vapour</u><u> </u><u>pressure</u><u> </u><u>of</u><u> </u><u>liquid</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>external</u><u> </u><u>pressure</u><u> </u><u>is</u><u> </u><u>called</u><u> </u><u>Boiling</u><u> </u><u>temperature</u><u>.</u><u>.</u>