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nirvana33 [79]
3 years ago
15

List all orbitals from 1s through 5s according to increasing energy for multielectron atoms. rank orbitals from smallest to larg

est energy. helpreset 3p2p

Chemistry
1 answer:
GaryK [48]3 years ago
3 0

Answer:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s

Explanation:

You can predict the order of orbital energies by constructing a diagram as shown below.

Follow the arrows to get the orbitals in order of increasing energy.

The order is

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s

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The compound adrenaline contains 56.79% c, 6.56% h, 28.37% o, and 8.28% n by mass. what is the empirical formula for adrenaline?
Phoenix [80]
To determine the empirical formula of the compound given, we need to determine the ratio of each element in the compound. To do that we assume to have 100 grams sample of the compound with the given composition. Then, we calculate for the number of moles of each element. We do as follows:<span>
         mass        moles
C       56.79        4.73
H       6.56          6.50
O       28.37        1.77
N      8.28           0.59

Dividing the number of moles of each element with the smallest value, we will have the empirical formula:

</span>         moles                 ratio
C       4.73     / 0.59       8
H       6.50     / 0.59      11
O       1.77     / 0.59       3
N        0.59    / 0.59       1<span>
</span><span>
The empirical formula would be C8H11O3N.</span>
8 0
3 years ago
How many grams od Mg(OH)2 will be needed to neutralize 25 mlod
irina [24]

Answer:

0.0073 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For HCl :

Molarity = 0.010 M

Volume = 25 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 25×10⁻³ L

Thus, moles of HCl :

Moles=0.010 \times {25\times 10^{-3}}\ moles

Moles of HCl  = 0.00025 moles

Considering the reaction shown below as:-

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

2 moles of HCl reacts with 1 mole of Mg(OH)_2

So,

1 moles of HCl reacts with 1/2 mole of Mg(OH)_2

Also,

0.00025 moles of HCl reacts with \frac{1}{2}\times 0.00025 mole of Mg(OH)_2

Mole of Mg(OH)_2 = 0.000125 moles

Molar mass of Mg(OH)_2 = 58.3197 g/mol

Mass = Moles*Molar mass = 0.000125\times 58.3197\ g = 0.0073 g

5 0
3 years ago
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Answer:

A=covalent B=low melting point

Explanation:

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8 0
3 years ago
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Brut [27]
Hope this helps.....

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:) Hope this helped.

8 0
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