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Tcecarenko [31]
3 years ago
12

What are (a) the charge and (b) the charge density on the surface of a conducting sphere of radius r whose potential is V (with

V = 0 at infinity)? State your answers in terms of the given variables, using ε0 if necessary.
Physics
1 answer:
Marat540 [252]3 years ago
7 0

Answer:

Part a)

Q = 4\pi \epsilon_0 r V

Part b)

\sigma = \frac{\epsilon_0 V}{r}

Explanation:

Part a)

As we know that potential of the sphere is given as

V = \frac{kQ}{r}

V = \frac{Q}{4\pi \epsilon_0 r}

now we have

Q = 4\pi \epsilon_0 r V

Part b)

Now we know that for conducting charged sphere whole charge is distributed over the surface of the sphere

so we will have

\sigma = \frac{Q}{4\pi r^2}

now we have

\sigma = \frac{4\pi \epsilon_0 r V}{4\pi r^2}

\sigma = \frac{\epsilon_0 V}{r}

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Part 2)

At 30% efficiency the mass converted equals

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8 0
3 years ago
– A man walks 50 meters due west, then 50 meters 60 north of west. Determine the magnitude and direction of the resultant disp
Fynjy0 [20]

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The diagram explains better.

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For the second:

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5 0
3 years ago
Read 2 more answers
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