<h3>Answer</h3>
option B)
19N
<h3>Explanation</h3>
If the object is at equilibrium, then the net force acting upon the object should be 0 N. Thus, if all the forces are added together, horizontal and vertical forces separately, then the resultant force (the vector sum) should be 0 Newton.
As we only need to find the magnitude of x-component of force F
so find all x component/horizontal forces acting on the object.
50cos(40) - 40cos(25) + 30cos(55) + x = 0
38.30 - 36.25 + 17.21 + x + = 0
19.26 + x = 0
x = - 19.26
x ≈ 19 (magnitude only)
Answer:
Explanation:
![v_f^2 = v_i^2-2a(x_f-x_i)](https://tex.z-dn.net/?f=v_f%5E2%20%3D%20v_i%5E2-2a%28x_f-x_i%29)
Subtract both sides by
:
![- v_i^2+v_f^2 = -2a(x_f-x_i)](https://tex.z-dn.net/?f=-%20v_i%5E2%2Bv_f%5E2%20%3D%20-2a%28x_f-x_i%29)
Divide both sides by -2*a:
![\frac{v_i^2 - v_f^2}{2a} =x_f-x_i](https://tex.z-dn.net/?f=%5Cfrac%7Bv_i%5E2%20-%20v_f%5E2%7D%7B2a%7D%20%3Dx_f-x_i)
Add both sides by
:
![x_i+\frac{v_i^2 - v_f^2}{2a} =x_f](https://tex.z-dn.net/?f=x_i%2B%5Cfrac%7Bv_i%5E2%20-%20v_f%5E2%7D%7B2a%7D%20%3Dx_f)
Subtract both sides by
:
![x_i=x_f-\frac{v_i^2 - v_f^2}{2a}](https://tex.z-dn.net/?f=x_i%3Dx_f-%5Cfrac%7Bv_i%5E2%20-%20v_f%5E2%7D%7B2a%7D)
Explanation:
Given parameters:
Distance hopped = 84m
Displacement = 84m due east
Time = 7s
Unknown:
Speed of kangaroo = ?
Velocity of kangaroo = ?
Solution:
To solve this problem,
Speed =
=
= 12m/s
Velocity =
=
= 12m/s due east
Answer:
option B is the correct answer
Explanation:
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