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NemiM [27]
3 years ago
10

The experimentation step of scientific inquiry involves _______.

Physics
2 answers:
Hoochie [10]3 years ago
8 0
<span>The answer is letter D.

The most important step in formulation a scientific inquiry is to first formulate a question. All answers sprung from a question that scratched the mind. Experimentation is not possible without the need to question, with this, the drive to find the answers is what motivates scientists or people involved in an experiment to find the answers that would suffice their curiosity. Questions are the basis of all the other choices above and is the most crucial step in the scientific inquiry.<span>
</span></span>
otez555 [7]3 years ago
5 0

Answer: c. choosing variables and controls.

A scientific inquiry is a fact finding inquiry regarding scientific reasons for natural phenomena. A scientific inquiry process involves development of questions, experimentation and drawing conclusion. The experimentation step of scientific inquiry involves choosing of variables and controls to derive data which can lead to conclusion of the scientific inquiry.

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An electron and a proton are held on an x axis, with the electron at x = + 1.000 m and the proton at x = - 1.000 m.how much work
aksik [14]
It is required an infinite work. The additional electron will never reach the origin.

In fact, assuming the additional electron is coming from the positive direction, as it approaches x=+1.00 m it will become closer and closer to the electron located at x=+1.00 m. However, the electrostatic force between the two electrons (which is repulsive) will become infinite when the second electron reaches x=+1.00 m, because the distance d between the two electrons is zero:
F=k_e  \frac{q_e q_e}{d^2}
So, in order for the additional electron to cross this point, it is required an infinite amount of work, which is impossible.
5 0
3 years ago
If a sample of a(
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3 years ago
List three measurements with different units this are equal to 5 meters
olganol [36]
5kg
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6 0
3 years ago
A mass of 0.450 kg rotates at constant speed with a period of 1.45 s at a radius R of 0.140 m in the apparatus used in this labo
Mamont248 [21]

Answer:

1.603 s

Explanation:

Given that

Initial mass, = 0.45 kg

Initial period, = 1.45 s

Initial radius, = 0.14 m

Final mass, = 0.55 kg

Final period, = ?

Final radios, = 0.14 m

Since we are finding the rotation period of two masses of same radius, we can assume that the outward force is the same in both cases. This means that

m₁r₁ω₁² = m₂r₂ω2²

Where, ω = 2π/T, on substituting, we have

0.45 * 0.14 * (2π / 1.45)² = 0.550 * 0.14 * (2π / T₂)²

0.45 / 1.45² = 0.550 / T₂²

T₂² = 0.550 * 1.45² / 0.45

T₂² = 2.56972

T₂ = √2.56972

T₂ = 1.603 sec

7 0
2 years ago
A star with the same mass and diameter as the sun rotates about a central axis with a period of about 24.0 days. Suppose that th
Mila [183]

Answer:

a)  w = 2.52 10⁷ rad / s, b)  K / K₀ = 1.19 10⁴

Explanation:

a) We can solve this exercise using the conservation of angular momentum.

Initial instant. Before collapse

         L₀ = I₀ w₀

Final moment. After the collapse

         L_f = I w

angular momentum is conserved

        L₀ = L_f

         I₀ w₀ = I w                 (1)

         

The moment of inertia of a sphere is

        I = 2/5 m r²

we take from the table the mass and diameter of the star

        m = 1,991 10³⁰ kg

        r₀ = 6.96 10⁸ m

        r = 6.37 10⁶ m

to find the angular velocity let's use

       w = L / T

where the length of a circle is

      L = 2π r

      T = 24 days (24 h / 1 day) (3600 s / 1h) = 2.0710⁶ s

we substitute

      w = 2π r / T

      wo = 2π 6.96 10⁸ / 2.07 10⁶

      wo = 2.1126 10³ rad / s

we substitute in equation 1

      w = \frac{I_o}{I}

      w = 2/5 mr₀² / 2/5 m r² w₀

      w = (\frac{r_o}{r}) ² wo

      w = (6.96 10⁸ / 6.37 10⁶) ² 2.1126 10³

      w = 2.52 10⁷ rad / s

b) the kinetic energy ratio

      K = ½ m w²

       K₀ = ½ m w₀²

       K = ½ m w²

       K / K₀ = (w / wo) ²

       K / K₀ = 2.52 10⁷ / 2.1126 10³

       K / K₀ = 1.19 10⁴

7 0
3 years ago
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