Question

How strong is the attractive force between a glass rod with a 0.700 μC charge and a silk cloth with a –0.600 μC charge, which are 12.0 cm apart, using the approximation that they act like point charges?

Answer 1

Answer:

$F=0.26N$

Explanation:

Assuming that thet act like point charges, the attractive force is given by Coulomb's law:

$F=\frac{kq_1q_2}{d^2}$

Where k is the Coulomb constant, $q_1$ and $q_2$ are the magnitudes of the point charges and d is the distance of separation between them. Thus, we replace the given values and get how strong is the attractive force between them:

$F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(0.7*10^{-6}C)(-0.6*10^{-6}C)}{(12*10^{-2}m)^2}\\F=0.26N$