Explanation:
If an object has a moment of inertia I₀ about an axis, then the moment of inertia about a different, parallel axis is I = I₀ + md², where d is the distance between the axes.
For example, consider a horizontal thin rod rotating about a vertical axis passing through its center. It has mass m and length L. Its moment of inertia is known to be I = 1/12 mL².
Now consider the same rod, but this time we move the axis of rotation L/2 to the end of the rod. We can use parallel axis theorem to find the new moment of inertia:
I = I₀ + md²
I = 1/12 mL² + m (L/2)²
I = 1/12 mL² + 1/4 mL²
I = 1/3 mL²
Answer:Given:
Initial speed of fugitive, v0 = 0 m/s
Final speed, vf = 6.1 m/s
acceleration, a = 1.4 m/s^2
Speed of train, v = 5.0 m/s
Solution:
t = (vf-v0)/a
t = (6.1-0)/1.4
t =4.36 s
Distance traveled by train, x_T =v*t
x_T =5*4.36 = 21.8 m
Distance travelled by fugitive, x_f = v0*t+1/2at^2
x_f = 0*4.36+1/2*1.4*4.36^2
x_f =13.31 m
5*t = v(t-4.36)+x_f
5*t=6.1*(t-4.36)+13.31
solve for t, we get
t = 12.08 s
The fugitive takes 12.08 s to catch up to the empty box car.
Distance traveled to reach the box car is
X_T = v*t
X_T = 5*12.08 s
X_T = 60.4 m
Explanation:
The weight would be 62.92.
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