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stiks02 [169]
3 years ago
5

Is the relationship between volume and pressure direct or indirect? Explain your answer

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer:

Boyle's Law is a relationship between pressure and volume. In this relationship, pressure and volume have an inverse relationship when temperature is held constant. If there is a decrease in the volume there is less space for molecules to move and therefore they collide more often, increasing the pressure.

Explanation:

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Describe how the structure of a red blood cell is related to its function.
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The red blood cell is made to transport oxygen around the body.

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1. Consider the reaction: N2 (g) + O2 (g)  2NO (g) + Cl2 (g) A reaction mixture at 400 C has the following composition: [NO] =
Olegator [25]

Answer:

The reaction is not at the equilibrium, we have more products than reactants.

Explanation:

Step 1: Data given

Temperature = 400 °C

When Q=K, this means the system is at equilibrium. There will not be a shift to either the left or the right.

When Q<K,it means we have more reactants than products. The system will, as reaction, make more products, this will cause the equilibrium to move to the right.

When Q>K,it means we have more products than reactants. The system will, as reaction, make less products and more reactants, this will cause the equilibrium to move to the left.

[NO] = 0.01 M

[N2] = 0.001 M

[O2] = 0.001 M

Kc = 0.0156

Step 2: The balanced equation

N2 (g) + O2 (g) ⇆ 2NO (g) + Cl2 (g)

Step 3: Calculate Q

Q = [NO]²/[N2][O2]

Q = 0.01²/(0.01*0.001)

Q = 10

Q>>Kc

This means we have more products than reactants. The system will, as reaction, make less products and more reactants, this will cause the equilibrium to move to the left.

The reaction is not at the equilibrium, we have more products than reactants.

4 0
3 years ago
What is the quantity of heat (in kJ) associated with cooling 185.5 g of water from 25.60°C to ice at -10.70°C?Heat Capacity of S
Cerrena [4.2K]

Taking into account the definition of calorimetry, sensible heat and latent heat,  the amount of heat required is 37.88 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Sensible heat</h3>

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

  • <u><em>25.60 °C to 0 °C</em></u>

First of all, you should know that the freezing point of water is 0°C. That is, at 0°C, water freezes and turns into ice.

So, you must lower the temperature from 25.60°C (in liquid state) to 0°C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • c= Heat Capacity of Liquid= 4.184 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= 0 °C - 25.60 °C= - 25.6 °C

Replacing:

Q1= 4.184 \frac{J}{gC}× 185.5 g× (- 25.6 °C)

Solving:

<u><em>Q1= -19,868.98 J</em></u>

  • <u><em>Change of state</em></u>

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

n= 185.5 grams× \frac{1mol}{18 grams}= 10.30 moles, where 18 \frac{g}{mol} is the molar mass of water, that is, the amount of mass that a substance contains in one mole.

ΔHfus= 6.01 \frac{kJ}{mol}

Replacing:

Q2= 10.30 moles×6.01 \frac{kJ}{mol}

Solving:

<u><em>Q2=61.903 kJ= 61,903 J</em></u>

  • <u><em>0 °C to -10.70 °C</em></u>

Similar to sensible heat previously calculated, you know:

  • c = Heat Capacity of Solid = 2.092 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= -10.70 °C - 0 °C= -10.70 °C

Replacing:

Q3= 2.092 \frac{J}{gC} × 185.5 g× (-10.70) °C

Solving:

<u><em>Q3= -4,152.3062 J</em></u>

<h3>Total heat required</h3>

The total heat required is calculated as:  

Total heat required= Q1 + Q2 +Q3

Total heat required=-19,868.98 J + 61,903 J -4,152.3062 J

<u><em>Total heat required= 37,881.7138 J= 37.8817138 kJ= 37.88 kJ</em></u>

In summary, the amount of heat required is 37.88 kJ.

Learn more about calorimetry:

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