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zheka24 [161]
3 years ago
9

For a brass alloy, the following engineering stresses produce the corresponding plastic engineering strains prior to necking:

Engineering
1 answer:
tatuchka [14]3 years ago
4 0

Answer:

<h2><em> </em>The engineering stress necessary to produce an engineering strain of 0.28 is 339 Mpa</h2>

Explanation:

<em>On the basis of this information, we are going to compute the engineering stress necessary to produce an engineering strain of 0.28.</em>

<h2>Engineering           Engineering </h2><h2> Stress (MPa)             Strain</h2><h2>315                             0.105 </h2><h2>340                           0.220 </h2>

For clarity and you will find the solving in the attached file for your reference.

should you need further information do let me know.

​  

 

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Is it possible to have a heat engine with efficiency of 100%?
Alex17521 [72]

Answer:

No

Explanation:

Heat engines are used for converting the heat into mechanical energy which is used for doing mechanical work.

The efficiency of heat engine is the fraction of mechanical energy to the thermal energy. The efficiency can not be 100% as some of the energy always loss due to friction and motion of the body parts of the heat engine.

7 0
2 years ago
What are the de Broglie frequencies and wavelengths of (a) an electron accelerated to 50 eV (b) a proton accelerated to 100 eV
DaniilM [7]

Answer:

(a) De-Brogie wavelength is 0.173 nm and frequency is 2.42 x 10^16 Hz

(b) De-Brogie wavelength is 2.875 pm and frequency is 4.8 x 10^16 Hz

Explanation:

(a)

First, we need to find velocity of electron. Since, it is accelerated by electric potential. Therefore,

K.E of electron = (1/2)mv² = (50 eV)(1.6 x 10^-19 J/1 eV)

(1/2)mv² = 8 x 10^(-18) J

Mass of electron = m = 9.1 x 10^(-31) kg

Therefore,

v² = [8 x 10^(-18) J](2)/(9.1 x 10^(-31) kg)

v = √1.75 x 10^13

v = 4.2 x 10^6 m/s

Now, the de Broglie's wavelength is given as:

λ = h/mv

where,

h = Plank's Constant = 6.626 x 10^(-34) kg.m²/s

Therefore,

λ = (6.626 x 10^(-34) kg.m²/s)/(9.1 x 10^(-31) kg)(4.2 x 10^6 m/s)

<u>λ = 0.173 x 10^(-9) m = 0.173 nm</u>

The frequency is given as:

Frequency = f = v/λ

f = (4.2 x 10^6 m/s)/(0.173 x 10^(-9) m)

<u>f = 2.42 x 10^16 Hz</u>

(b)

First, we need to find velocity of proton. Since, it is accelerated by electric potential. Therefore,

K.E of proton = (1/2)mv² = (100 eV)(1.6 x 10^-19 J/1 eV)

(1/2)mv² = 1.6 x 10^(-17) J

Mass of proton = m = 1.67 x 10^(-27) kg

Therefore,

v² = [1.6 x 10^(-17) J](2)/(1.67 x 10^(-27) kg)

v = √1.916 x 10^10

v = 1.38 x 10^5 m/s

Now, the de Broglie's wavelength is given as:

λ = h/mv

where,

h = Plank's Constant = 6.626 x 10^(-34) kg.m²/s

Therefore,

λ = (6.626 x 10^(-34) kg.m²/s)/(1.67 x 10^(-27) kg)(1.38 x 10^5 m/s)

<u>λ = 2.875 x 10^(-12) m = 2.875 pm</u>

The frequency is given as:

Frequency = f = v/λ

f = (1.38 x 10^5 m/s)/(2.875 x 10^(-12) m)

<u>f = 4.8 x 10^16 Hz</u>

6 0
3 years ago
The 15-Mg tank car A and 25-Mg freight car B travel towards each other with the velocities shown. If the coefficient of restitut
irga5000 [103]

The speed of the car A is 6.05 m/s and  the speed of the car B just after the collision 7.65 m/s.

Ma=15 mg , Mb=25mg

Vai=5 m/s   vbi=7 m/s

We know coeffecient of restitution

e=|Vaf-Vbf/Vai-Cbi|

0.8=|Vaf-Vbf/5-7|

Vaf-Vbf=1.6

MaVa+mbVb=MaVaf+MbVbf

15*5*25*7=15Vaf+25Vbf

3Vaf+5Vbf=50

sovleving eq 1 and 2

Vbf =6.05 m/s

Vaf=7.65 m/s

The speed of a change in an object's location in any direction. The distance traveled divided by the time required to travel that distance is the definition of speed.Due to its lack of magnitude and merely having a direction, speed is a scalar number. The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is calculated.

Learn more about speed here:

brainly.com/question/28224010

#SPJ4

6 0
1 year ago
When in regular operation, ash and other debris should be removed _______ from the combustion chamber of a wood-burning heater.
Klio2033 [76]

Answer:

    Daily from the combustion chamber of a wood-burning heater.

<h3>Explanation:</h3>
  • As a wood stove heats up, it radiates heat through the walls and top of the stove
  • This radiant heat warms the immediate area and can be carried into other parts of the home via the home's natural airflow.
  • Electric or convection-powered fans can help circulate this heat to warm a larger area.

To learn more about it, refer

to brainly.com/question/23275071

#SPJ4

8 0
1 year ago
Explain why failure of this garden hose occurred near its end and why the tear occurred along its length. Use numerical values t
alukav5142 [94]

Answer:

  • hoop stress
  • longitudinal stress
  • material used

all this could led to the failure of the garden hose and the tear along the length

Explanation:

For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :

hoop stress ( which acts along the circumference of the pipe):

αh = \frac{PD}{2T}     EQUATION 1

and Longitudinal stress ( acting along the length of the pipe )

αl = \frac{PD}{4T}       EQUATION 2

where p = water pressure inside the hose

          d = diameter of hose, T = thickness of hose

we can as well attribute the failure of the hose to the material used in making the hose .

assume for a thin cylindrical pipe material used to be

\frac{D}{T} ≥  20

insert this value into equation 1

αh = \frac{20 *30}{2}  = 60/2 = 30 psi

the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose

8 0
2 years ago
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