For a brass alloy, the following engineering stresses produce the corresponding plastic engineering strains prior to necking:
1 answer:
Answer:
<h2><em> </em>The engineering stress necessary to produce an engineering strain of 0.28 is 339 Mpa</h2>Explanation:
<em>On the basis of this information, we are going to compute the engineering stress necessary to produce an engineering strain of 0.28.</em>
<h2>Engineering Engineering </h2><h2> Stress (MPa) Strain</h2><h2>315 0.105 </h2><h2>340 0.220 </h2>For clarity and you will find the solving in the attached file for your reference.
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Answer:
W = 2695.14 lb
Explanation:
given,
side of cube = 3 ft
density of the cube = 3.1 slugs/ft³
we know,
mass = density x volume
volume = 3³ = 27 ft³
mass = 3.1 x 27
m = 83.7 slugs.
weight calculation
converting mass from slug to pound
weight of 1 slug is equal to 32.2 lb
now,
weight of the cube is equal to
W = 83.7 slugs x 32.2 lb/slug
W = 2695.14 lb
hence, weight is equal to W = 2695.14 lb