For a brass alloy, the following engineering stresses produce the corresponding plastic engineering strains prior to necking:
1 answer:
Answer:
<h2><em> </em>The engineering stress necessary to produce an engineering strain of 0.28 is 339 Mpa</h2>Explanation:
<em>On the basis of this information, we are going to compute the engineering stress necessary to produce an engineering strain of 0.28.</em>
<h2>Engineering Engineering </h2><h2> Stress (MPa) Strain</h2><h2>315 0.105 </h2><h2>340 0.220 </h2>For clarity and you will find the solving in the attached file for your reference.
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Answer:
Explanation:
Assumptions is that
1. The flow is an unsteady one
2. Bubbles diameter is constant
3. The bubble velocity is slow
4. There is no homogenous reaction
5. It has a one dimensional flux model along the radial direction
Answer:
6.37 inch
Explanation:
Thinking process:
We need to know the flow rate of the fluid through the cross sectional pipe. Let this rate be denoted by Q.
To determine the pressure drop in the pipe:
Using the Bernoulli equation for mass conservation:
thus
The largest pressure drop (P1-P2) will occur with the largest f, which occurs with the smallest Reynolds number, Re or the largest V.
Since the viscosity of the water increases with temperature decrease, we consider coldest case at T = 50⁰F
from the tables
Re= 2.01 × 10⁵
Hence, f = 0.018
Therefore, pressure drop, (P1-P2)/p = 2.70 ft
This occurs at ae presure change of 1.17 psi
Correlating with the chart, we find that the diameter will be D= 0.513
= <u>6.37 in Ans</u>