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Elan Coil [88]
3 years ago
5

If a worker currently makes $425.00 per week, what Is the gross amount they’ll earn if they work every week of the year

Engineering
1 answer:
olga nikolaevna [1]3 years ago
4 0

Answer:

we know that

A worker currently makes \$425.00 per week

remember that

1\ year=52\ weeks

so

by proportion find the amount that the worker will earn in one year

\frac{425}{1} \frac{\$}{week} =\frac{x}{52} \frac{\$}{weeks} \\ \\x=52*425 \\ \\x=\$22,100

therefore

the answer is

\$22,100

Explanation:

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A motor takes 38 amperes on a 220-volt circuit. Find the horsepower output (hp) of the motor shown with an efficiency of 90%. Ex
IrinaK [193]

This question involves the concepts of power and current.

The power output of the motor is "10.08 hp".

<h3>Power Output</h3>

The power output of the motor can be found using the following formula:

P = ηVI

where,

  • P = Power = ?
  • η = efficiency = 90 % = 0.9
  • I = current = 38 A
  • V = potential difference = 220 V

Therefore,

P = (0.9)(38 A)(220 V)

P = 7524 watt

converting this to horsepower:

P = (7524 watt)(\frac{1\ hp}{746\ watt})

P = 10.08 hp

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7 0
1 year ago
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almond37 [142]

Answer:

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Explanation:

4 0
3 years ago
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Technician A says that squeeze-type resistance spot welding (STRSW) may be used on open butt joints. Technician B says that repl
Mamont248 [21]

Answer:

B only

Explanation:

Squeeze-type resistance spot welding (STRSW)is a type of electric resistance welding that brings about the weld on interfacing sheet metal pieces through which heat generated from electric resistance bring about fusion and welding of the two pieces together

Therefore, it is not meant for opening but joints but it can be used for making replacement spot welds adjacent to the original spot weld due to the smaller heat affected zone (HAZ) created by the STRSW process.

6 0
3 years ago
A 46.0-g meter stick is balanced at its midpoint (50.0 cm, zero point is a left end of stick). Then a 210.0-g weight is hung wit
Anna71 [15]

Clockwise torque due to 100g is 0.1029 Nm and 200g is 1.4406 Nm. Clockwise torque due to stick mass is 0.2254 Nm and Counter-clockwise torque due to normal force is 1.7689 Nm.            

<h3>What is clockwise torque?</h3>

The right-hand rule for cross products determines the direction of torque, which is calculated as the cross product of force and distance. Your thumb will point in the direction of the torque if you place your palm in the direction of the applied force and extend your fingers from the pivot point in that direction.

A related right-hand rule relates the direction of the rotation to the direction of the torque. Your fingers will curl in the direction of rotation if you point your thumb in the direction of the torque.

Positive torques cause counter clockwise rotation, while negative torques cause clockwise rotation.

The sum of all torques must be zero at equilibrium since an object in equilibrium has no net torque.

When the force is applied in a direction perpendicular to the line connecting the pivot and the force, the torque is at its greatest.

You can calculate the torque's magnitude using

                                             \begin{displaymath}\tau =rF_{\bot }=rF\sin \theta .\end{displaymath}

To solve problems involving torques, follow these eight steps: read the issue, create a free-body diagram, locate the pivot point, write down the expressions for all torques, For equilibrium conditions, set the sum of torques to zero, list all known variables, pick the desired variable(s), write down equations involving those variable(s), solve the equations, plug in numbers, and test your solution.

Clockwise torque due to 100 g                                                                         ⇒ T1 = 0.105* 9.8* 0.1 = 0.1029 Nm

Clockwise torque due to 200 g                                                                                                      ⇒ T2 = 0.210* 9.8* 0.7 = 1.4406 Nm

Clockwise torque due to stick mass                                                                               ⇒ T3 = 0.046* 0.5* 9.8 =0.2254 Nm

Counter-clockwise torque due to normal force                                                                             ⇒ T4 = (0.046 + 0.21 + 0.105)*9.8* 0.5 = 1.7689 Nm

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7 0
1 year ago
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Allisa [31]

Answer:

A

Explanation:

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3 years ago
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