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3 years ago

If a worker currently makes $425.00 per week, what Is the gross amount they’ll earn if they work every week of the year

Engineering

1 answer:

olga nikolaevna [1]3 years ago

4 0

Answer:

we know that

A worker currently makes \$425.00 per week

remember that

1\ year=52\ weeks

by proportion find the amount that the worker will earn in one year

\frac{425}{1} \frac{\$}{week} =\frac{x}{52} \frac{\$}{weeks} \\ \\x=52*425 \\ \\x=\$22,100

therefore

the answer is

\$22,100

Explanation:

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Steam at a pressure of 100 bar and temperature of 600 °C enters an adiabatic nozzle with a velocity of 35 m/s. It leaves the noz

butalik [34]

Answer:

Exit velocity $V_2=1472.2$ m/s.

Explanation:

Given:

At inlet:

$P_1=100 bar,T_=600°C,V_1=35m/s$

Properties of steam at 100 bar and 600°C

$h_1=3624.7\frac{KJ}{Kg}$

At exit:Lets take exit velocity $V_2$

We know that if we know only one property inside the dome then we will find the other property by using steam property table.

Given that dryness or quality of steam at the exit of nozzle is 0.85 and pressure P=80 bar.So from steam table we can find the other properties.

Properties of saturated steam at 80 bar

$h_f= 1316.61\frac{KJ}{Kg} ,h_g= 2757.8\frac{KJ}{Kg}$

So the enthalpy of steam at the exit of turbine

$h_2=h_f+x(h_g-h_f)\frac{KJ}{Kg}$

$h_2=1316.61+0.85(2757.8-1316.61)\frac{KJ}{Kg}$

$h_2=2541.62\frac{KJ}{Kg}$

Now from first law for open system

$h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w$

In the case of adiabatic nozzle Q=0,W=0

$3624.7+\dfrac{35^2}{2000}+0=2541.62+\dfrac{(V_2)^2}{2000}+0$

$V_2=1472.2$ m/s

So Exit velocity $V_2=1472.2$ m/s.

4 0

3 years ago

6.28 A six-lane freeway (three lanes in each direction) in rolling terrain has 10-ft lanes and obstructions 4 ft from the right

dimulka [17.4K]

Answer:

Assume Base free flow speed (BFFS) = 70 mph

Lane width = 10 ft

Reduction in speed corresponding to lane width, fLW = 6.6 mph

Lateral Clearance = 4 ft

Reduction in speed corresponding to lateral clearance, fLC = 0.8 mph

Interchanges/Ramps = 9/ 6 miles = 1.5 /mile

Reduction in speed corresponding to Interchanges/ramps, fID = 5 mph

No. of lanes = 3

Reduction in speed corresponding to number of lanes, fN = 3 mph

Free Flow Speed (FFS) = BFFS – fLW – fLC – fN – fID = 70 – 6.6 – 0.8 – 3 – 5 = 54.6 mph

Peak Flow, V = 2000 veh/hr

Peak 15-min flow = 600 veh

Peak-hour factor = 2000/ (4*600) = 0.83

Trucks and Buses = 12 %

RVs = 6 %

Rolling Terrain

fHV = 1/ (1 + 0.12 (2.5-1) + 0.06 (2.0-1)) = 1/1.24 = 0.806

fP = 1.0

Peak Flow Rate, Vp = V / (PHV*n*fHV*fP) = 2000/ (0.83*3*0.806*1.0) = 996.54 ~ 997 veh/hr/ln

Vp < (3400 – 30 FFS)

S = FFS

S = 54.6 mph

Density = Vp/S = (997) / (54.6) = 18.26 veh/mi/ln

7 0

3 years ago

How many points do you need to define for the rectangle

Rudik [331]

Answer:

Two points

Explanation:

3 0

3 years ago

Which of these materials are insulators? Select the THREE (3) that apply.

lubasha [3.4K]

Answer:

wool, rubber, and plastic

Explanation:

5 0

2 years ago

A horizontal angle was measured by repetition six times with a total station. If the initial display reading was 21o33'18" and t

KIM [24]

Answer:

The value of the angle is 107° 46' 46''

Explanation:

we know that

To find out the value of the angle , subtract the initial display reading from the final reading

Remember that

1°=60'

1'=60''

1°=3,600''

we have

Initial display reading=21° 33' 18''

Convert to seconds

21(3,600)+33(60)+18=77,598''

Final display reading=129° 20' 04''

Convert to seconds

129(3,600)+20(60)+4=465,604''

Find the difference

465,604''-77,598''=388,006''

Convert 388,006'' to degrees

388,006''/3,600=107.7794°

Convert 0.7794° to minutes

0.7794(60)=46.764'

Convert 0.764' to seconds

0.764(60)=45.84''=46''

therefore

The value of the angle is

107° 46' 46''

4 0

3 years ago