Question

You are assigned the design of a cylindrical, pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 m/s2. The pressure at the surface of the water will be 110 kPa , and the depth of the water will be 13.6 m . The pressure of the air outside the tank, which is elevated above the ground, will be 95.0 kPa

Answer 1

Answer:

The water tank have to support a pressure of 50,456 Pa.

Explanation:

To design the cylindrical, pressurised water tank, we need to calculate the total pressure that it's being applied to tank, in order to know how strong we need to make it.

The total pressure (P) on the tank is always the sum of all pressures that are involved, external air pressure (P1), inside pressure (P2) and the pressure due to the mass of water (P3).

So, The external air pressure (P1) is 95.0 kPa.

The inside pressure (P2) is 110 kPa.

The pressure due to the mass of water (P3) will be calculated with: $P_{3}=pgh$; where p is density of the water, g is the gravity and h the height.

Using the values given g = 3.71 m/s2; h =  13.6 m and p = 1000 kg/m3.

$P_{3}=(1000\frac{kg}{m^{3} } )(3.71\frac{m}{s^{2} } )(13.6m) = 50,456 Pa.$

Therefore, we need to design an water tank strong enough to endure a pressure of 50,456 Pa.