Answer: I believe the answer is speed up.
Explanation: This is because when water heats up the molecules move farther apart from eachother they speed up, eventually causing the water to boil.
The solution to the question would be C. The number 7 is needed to balance the equation, as by doing so, you will have the total correct amount of oxygen atoms on the left side as per the right side of the reaction.
(a) The speed of a satellite on a low lying circular orbit around this planet is 7,338.93 m/s.
(b) The minimum speed required for a satellite in order to break free permanently from the planet is 10,378.82 m/s.
(c) The radius of the synchronous orbit of a satellite is 69,801 km .
<h3>Speed of the satellite</h3>
v = √GM/r
where;
- M is mass of the planet
- r is radius of the planet
v = √[(6.67 x 10⁻¹¹ x 4.74 x 10²⁴) / (5870 x 10³)]
v = 7,338.93 m/s
<h3>Escape velocity of the satellite</h3>
v = √2GM/r
v = √[( 2 x 6.67 x 10⁻¹¹ x 4.74 x 10²⁴) / (5870 x 10³)]
v = 10,378.82 m/s
<h3>Speed of the satellite at the given period </h3>
v = 2πr/T
r = vT/2π
r = (7,338.93 x 16.6 x 3600 s) / (2π)
r = 69,801 km
Thus, the speed of a satellite on a low lying circular orbit around this planet is 7,338.93 m/s.
The minimum speed required for a satellite in order to break free permanently from the planet is 10,378.82 m/s.
The radius of the synchronous orbit of a satellite is 69,801 km .
Learn more about minimum speed here: brainly.com/question/6504879
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Answer:
b) q large and m small
Explanation:
q is large and m is small
We'll express it as :
q > m
As we know the formula:
F = Eq
And we also know that :
F = Bqv
F =
Bqv =
or Eq =
Assume that you want a velocity selector that will allow particles of velocity v⃗ to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.
Answer:
The speed of the center of mass of the two carts is 0.103 m/s
Explanation:
It is given that,
Mass of the air track cart, m₁ = 350 g = 0.35 kg
Velocity of air track cart, v₁ = 1.25 m/s
Mass of cart, m₂ = 280 g = 0.28 kg
Velocity of cart, v₂ = -1.33 m/s (it is travelling in opposite direction)
We need to find the speed of the center of mass of the two carts. It is given by the following relation as :
Hence, this is the required solution.