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Bogdan [553]
3 years ago
12

How do u cure a headache without any pills no bots or I will report u?

Physics
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

Try a Cold Pack. Use a Heating Pad or Hot Compress. Ease Pressure on Your Scalp or Head. Dim the Lights. Try Not to Chew. Hydrate. Get Some Caffeine. Practice Relaxation.

Dmitriy789 [7]3 years ago
5 0

Answer:

I usually just eat something or drink lots of water.

Explanation:

Hope this helps

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Gravity pushes against all objects, trying to crush it. What pushes against gravity in: a main sequence star, a white dwarf, a n
ololo11 [35]

Answer:

heat pressure, neutron degeneracy, electron degeneracy,nothing.

Explanation:

In main sequence star, gravity's inward pull is greatly balanced by the heat pressure. In the white dwarf, gravity is mainly balanced by the electron degeneracy pressure that arises from the fact that the electrons are fermions and they obey the Pauli's exclusion principle.  So there is no two electrons that have the same the four quantum numbers.

While in neutron star, the neutron degeneracy pressure obeys the Pauli's exclusion principle that gives rise to the degeneracy pressure and noting pushes against the gravity in the black hole. Therefore the correct option is the heat pressure, neutron degeneracy, electron degeneracy and nothing.

4 0
3 years ago
A 460 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exert
ollegr [7]

Answer:

The rocket should be launched at a horizontal distance of <u>6.45 m</u> left of the loop.

Explanation:

Given:

Mass of the rocket model (m) = 460 g = 0.460 kg [1 g = 0.001 kg]

Speed of the cart (v) = 3.0 m/s

Thrust force by the rocket engine (F) = 8.5 N

Vertical height of the loop (y) = 20 m

Let the horizontal distance left to the loop for launch be 'x'. Also, let 't' be the time taken by the rocket to reach the loop.

Now, there are two types of motion associated with the rocket- one is horizontal and the other vertical.

So, we will apply kinematics of motion in the two directions separately.

Vertical motion:

Given:

Force acting in the vertical direction is given as:

F_y=F-mg=8.5-0.46\times 9.8=3.992\ N

So, acceleration in the vertical direction is given as:

Acceleration = Force ÷ mass

a_y=\frac{F_y}{m}=\frac{3.992\ N}{0.46\ kg}=8.678\ m/s^2

Vertical displacement of rocket is same as the height of loop. So, y=20\ m

There is no initial velocity in the vertical direction. So, u_y=0\ m/s

Now, applying equation of motion in vertical direction. we have:

y=u_yt+\frac{1}{2}a_yt^2\\\\20=0+\frac{1}{2}\times 8.678t^2\\\\20=4.339t^2\\\\t^2=\frac{20}{4.339}\\\\t=\sqrt{\frac{20}{4.339}}=2.15\ s

Now, time taken to reach the loop is 2.15 s.

Horizontal motion:

There is no acceleration in the horizontal motion. So, displacement in the horizontal direction is equal to the product of horizontal speed and time.

Also, displacement of the rocket in the horizontal direction is nothing but the horizontal distance of its launch left of the loop. So,

x=vt\\\\x=3.0\ m/s\times 2.15\ s\\\\x=6.45\ m

Therefore, the rocket should be launched at a horizontal distance of 6.45 m left of the loop.

5 0
4 years ago
It takes 6 seconds for a stone to fall to the bottom of a mine shaft. how deep is the shaft
Margaret [11]
You need the kinematic equation for distance as a function of acceleration:

d = [v(initial) *t] + 0.5a*t^{2}

where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
t = time of fall

if the stone started at rest then v(initial) = 0 making the equation simply 0.5a * t^{2}

Let me know if you still need further help :)
6 0
3 years ago
In the expression 3x2y + 4x – 5x2y, are the terms 3x2y and –5x2y like terms? Explain by providing support for your answer.
Zanzabum
Https://www.cymath.com/answer?q=%205%2B4i%2F6%2B8i
this site can help you 
3 0
3 years ago
Read 2 more answers
Which table is it I’ll mark brainlest
alexira [117]

Answer:

we need the graph to answer the question.

5 0
3 years ago
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