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Amiraneli [1.4K]
3 years ago
13

7. Write a formula for each of the following:

Chemistry
2 answers:
Advocard [28]3 years ago
7 0

Answer:

\huge \boxed{{C_{22} H_{46} \ \ \ \ C_{17} H_{34}  \ \ \ \ C_{13} H_{24}}}

Explanation:

alkanes \ \Rightarrow \ C_n H_{2n+2}

C_{22} H_{2(22)+2}

C_{22} H_{44+2}

C_{22} H_{46}

alkenes \ \Rightarrow \ C_n H_{2n}

C_{17} H_{2(17)}

C_{17} H_{34}

alkynes \ \Rightarrow \ C_n H_{2n-2}

C_{13} H_{2(13)-2}

C_{13} H_{26-2}

C_{13} H_{24}

sergeinik [125]3 years ago
3 0

Answer : The formula for each of the following is:

(a) C_{22}H_{46}

(b) C_{17}H_{34}

(c) C_{13}H_{24}

Explanation :

  • Alkanes are hydrocarbon in which the carbon atoms are connected with single covalent bonds.

The general formula of alkanes is C_n H_{2n+2} where n is the number of the carbon atoms present in a molecule of alkane.

  • Alkenes are hydrocarbon in which the carbon atoms are connected with double covalent bonds.

The general formula of alkenes is C_n H_{2n} where n is the number of the carbon atoms present in a molecule of alkene.

  • Alkynes are hydrocarbon in which the carbon atoms are connected with triple covalent bonds.

The general formula of alkynes is C_n H_{2n-2} where n is the number of the carbon atoms present in a molecule of alkyne.

(a) An alkane with 22 carbon atoms

Putting n = 22 in the general formula of alkane, we get the formula of alkane as, C_{22}H_{2(22)+2} or C_{22}H_{46}

(b) An alkene with 17 carbon atoms

Putting n = 17 in the general formula of alkene, we get the formula of alkene as, C_{17}H_{2(17)} or C_{17}H_{34}

(c) An alkyne with 13 carbon atoms

Putting n = 13 in the general formula of alkyne, we get the formula of alkyne as, C_{13}H_{2(13)-2} or C_{13}H_{24}

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3 0
3 years ago
What volume would 0.735 moles of O2 gas occupy at STP
tatiyna

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ =  0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

                   No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

              No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

                0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

              Volume of O₂ = 0.735 x 22.4 dm³/ mol

              Volume of O₂ = 16.5 dm³

So,

the volume of O₂ at STP is 16.5 dm³

6 0
3 years ago
What’s the density if the mass is 40.8g and the volume is 60mL?
luda_lava [24]

Answer:

We have the final answer as

<h2>0.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 40.8 g

volume = 60 mL

The density is

density =  \frac{40.8}{60}  \\

We have the final answer as

<h3>0.68 g/mL</h3>

Hope this helps you

8 0
3 years ago
Identify the missing coefficient in the following equation:<br><br>3<br><br>2<br><br>1<br><br>0
Pie

Answer:

2

Explanation:

In balancing nuclear reactions the mass number and atomic numbers are usually conserved. This implies that from the given equation, the sum of the number of the subscript on the right hand side must be equal to that on the left hand side. This also applies to the superscript:

   For the mass numbers(superscript):

   235 + 1 = 1 + 139 + 95

       236 = 235

This is not balanced

  For the atomic number:

  92 + 0 = 0 + 53 + 39

      92 = 92

This is balanced.

We simply inspect to see how to balance the mass number.

By putting a coefficient of 2 behind the neutron atom, the equation becomes balanced.

7 0
3 years ago
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