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egoroff_w [7]
3 years ago
14

En que consiste la "Temperatura Curie"

Physics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:En la física y ciencia de los materiales , la temperatura de Curie ( T C ), o punto de Curie , es la temperatura por encima del cual ciertos materiales pierden sus magnéticos permanentes propiedades, para ser reemplazado por magnetismo inducido .

Explanation:

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A bowling ball with a mass of 9 kg is moving at a speed of 4 m/s. What is its
Ilia_Sergeevich [38]
I’m pretty sure it’s B
4 0
3 years ago
Please someone help me.
katovenus [111]

Answer:

acceleration of the car is 3 m\s^2

Explanation:

from rest means the initial velocity (vi) is zero

time = 5s

final velocity (vf) = 15m\s

a = vf - vi \ t

a = (15-0) \ 5

a= 3 m\s^2

which means that the car is speeding up 3 meters every second

5 0
4 years ago
A block moves up a 30 degree incline under the action of three applied forces. F1 is horizontal and of magnitude 40 N. F2 is nor
Alja [10]

Answer

given,

F₁ is horizontal = 40 N

F₂ is normal = 20 N

F₃ is parallel = 30 N

work done by

W₂ = 0 as force is acting perpendicular to the direction of motion.

as the motion moved to 0.8 cm

W₃ = F₃ x d

W₃ = 30 x 0.8

W₃ = 24 J

W₁ = F₁ x d

W₁ = F₁ cos ∅ x d

W₁ = 40 cos 30⁰ x 0.8

W₁ = 27.21 J

4 0
4 years ago
32g of water at 60°C is poured into 60g of cold water at 15°C, which is contained in a
Anestetic [448]

Explanation:

Let thermal capacity of the vessel be C' J K-1

Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J

Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J

Heat energy taken by vessel = C' x (30 - 20) = 10 C' J

If there is no loss of heat energy,

Heat energy given by hot water = Heat energy taken by cold water and vessel

or 5040 = 2100 + 10 C'

or 10 C' = 2940

or C'= 294 J K-1

Thus, thermal capacity of vessel = 294 J K-1.

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7 0
3 years ago
Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thou
Leona [35]

Answer:

F=2.84*10^{-26}N  & -y direction

F=2.84*10^{-26}N & +y direction

Explanation:

From the question we are told that:

Speed of electron V_e=3.83 * 10^5 m/s +x direction

Earths magnetic field B_e=3.04 * 10^-^8 +z direction

a)

Generally the equation for magnetic force F_m is mathematically given by

F=q(V_e*B_e)

where

q=1.6*10^{-19}c\\\=i*\=z=-\=j

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

F=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N  -y direction

b)

Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by

\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)

\=F'=-2.84*10^{-26}N \=j

Magnitude & Direction

F=2.84*10^{-26}N & +y direction

5 0
3 years ago
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