i know can you plzz help me with this question im sorry i didt answer your question i just need hel.
 
        
             
        
        
        
Hi
The answer to this question is B. Reaction
 
        
             
        
        
        
Small evidence is also called trace evidence.
        
             
        
        
        
Answer:
50 N
Explanation:
Efficiency of a machine can't be more than 1, so I assume you mean 40%.  (Remember, efficiency and mechanical advantage are not the same).
Efficiency is the ratio of work out of a system to the work in to the system.
e = Wout / Win
Work is force times distance, so:
e = (Fout × Dout) / (Fin × Din)
Rearranging:
Fin = (Fout × Dout) / (e × Din)
Fin = (Fout / e) × (Dout / Din)
Fin = (Fout / e) / (Din / Dout)
We know that e = 0.40, and Fout = 120 N.  Since there are 6 pulleys, we also know that Din/Dout = 6.
F = (120 N / 0.4) / 6
F = 50 N
 
        
             
        
        
        
Answer:
  q = 8.61 10⁻¹¹ m
charge does not depend on the distance between the two ships.
it is a very small charge value so it should be easy to create in each one
Explanation:
In this exercise we have two forces in balance: the electric force and the gravitational force
           F_e -F_g = 0
           F_e = F_g
Since the gravitational force is always attractive, the electric force must be repulsive, which implies that the electric charge in the two ships must be of the same sign.
Let's write Coulomb's law and gravitational attraction
           
In the exercise, indicate that the two ships are identical, therefore the masses of the ships are the same and we will place the same charge on each one.
           k q² = G m²
           q =  m
    m
we substitute
            q =  m
   m
             q =  m
   m
            q = 0.861 10⁻¹⁰ m
            q = 8.61 10⁻¹¹ m
This amount of charge does not depend on the distance between the two ships.
It is also proportional to the mass of the ships with the proportionality factor found.
Suppose the ships have a mass of m = 1000 kg, let's find the cargo
             q = 8.61 10⁻¹¹ 10³
             q = 8.61 10⁻⁸ C
              
this is a very small charge value so it should be easy to create in each one