Your answer would be,
Molarity = moles of solute/volume of solution we needed, 29.22(g)(mol) of NaCI
= 29.22(g)/58.44(g)(mol^-1)(1)/1(L)
= 0.500(mol)(L^-1)
Hope that helps!!!
When Sodium chloride or table salt is a compound formed
when sodium loses its valence electron to chlorine, the type of bond formation
that takes place in sodium chloride is the Lewis Bond.
1. 100 C
2. Point B to C is the ices heat capacity
3. During the points D to E the bonds of the water molecules build up enough kinetic energy to break their intermolecular bonds (not intra), which can lead to gas.
4. Between points D and E the energy is being released the energy required is equivalent along the line.
5. Between point E and D the water is converting to water (condensation)
6. Energy is being released 2260 j/g
7. Yes, but only under extreme volumetric pressures
8. D and E or B and C
9. Freezing (the water is also becoming less dense)
10. Melting or if water already, absorbtion of energy
11. released.
Answer:
Step-by-step explanation:
Alright, lets get started.
Suppose they take t minutes to meet each other.
Distance covered by first friend in t minutes, = 0.2 *t=0.2∗t
Distance covered by second friend in t minutes , =0.15 *t=0.15∗t
Total distance is given as 7, so
0.2 t + 0.15 t = 70.2t+0.15t=7
0.35 t = 70.35t=7
t = 20t=20
means after 20minutes they will meet.
SO. the average speed is 10m: Answer
The enthalpy change : -196.2 kJ/mol
<h3>Further explanation </h3>
The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation
The enthalpy of formation measured in standard conditions (25 ° C, 1 atm) is called the standard enthalpy of formation (ΔHf °)
(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)
The value of ° H ° can be calculated from the change in enthalpy of standard formation:
∆H ° rxn = ∑n ∆Hf ° (product) - ∑n ∆Hf ° (reactants)
Reaction
2 H₂O₂(l)-→ 2 H₂O(l) + O₂(g)
∆H ° rxn = 2. ∆Hf ° H₂O - 2. ∆Hf °H₂O₂
