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2 years ago

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is?

Physics

2 answers:

cestrela7 [59]2 years ago

8 0

Answer: The kinetic energy of the ball is 25 J

Explanation:

Kinetic energy is defined as the energy which is possessed due to its motion.

It is also defined as the half of the product of mass of the object and square of the velocity of the object.

Mathematically,

$E_K=\frac{1}{2}mv^2$

where,

$E_K$ = kinetic energy of ball

m = mass of the ball = 0.5 kg

v = velocity of ball = 10 m/s

Putting values in above equation, we get:

$E_K=\frac{1}{2}\times 0.5\times (10)^2\\\\E_K=25J$

Hence, the kinetic energy of the ball is 25 J

Vlad1618 [11]2 years ago

3 0

KE= .5*M*V^2
.5*.5*10^2
=25Joules

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3 years ago

A 65 kg person jumps from a window to a fire net 18 m below, which stretches the net 1.1 m. Assume the net behaves as a simple s

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Answer:

0.03167 m

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Explanation:

x = Compression of net

h = Height of jump

g = Acceleration due to gravity = 9.81 m/s²

The potential energy and the kinetic energy of the system is conserved

$P_i=P_f+K_s\\\Rightarrow mgh_i=-mgx+\frac{1}{2}kx^2\\\Rightarrow k=2mg\frac{h_i+x}{x^2}\\\Rightarrow k=2\times 65\times 9.81\frac{18+1.1}{1.1^2}\\\Rightarrow k=20130.76\ N/m$

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$65\times 9.81\times (35+x)=\frac{1}{2}20130.76x^2\\\Rightarrow 10065.38x^2=637.65(35+x)\\\Rightarrow 35+x=15.785x^2\\\Rightarrow 15.785x^2-x-35=0\\\Rightarrow x^2-\frac{200x}{3157}-\frac{1000}{451}=0$

Solving the above equation we get

$x=\frac{-\left(-\frac{200}{3157}\right)+\sqrt{\left(-\frac{200}{3157}\right)^2-4\cdot \:1\left(-\frac{1000}{451}\right)}}{2\cdot \:1}, \frac{-\left(-\frac{200}{3157}\right)-\sqrt{\left(-\frac{200}{3157}\right)^2-4\cdot \:1\left(-\frac{1000}{451}\right)}}{2\cdot \:1}\\\Rightarrow x=1.52, -1.45$

The compression of the net is 1.52 m

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