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g100num [7]
3 years ago
8

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is?

Physics
2 answers:
cestrela7 [59]3 years ago
8 0

<u>Answer:</u> The kinetic energy of the ball is 25 J

<u>Explanation:</u>

Kinetic energy is defined as the energy which is possessed due to its motion.

It is also defined as the half of the product of mass of the object and square of the velocity of the object.

Mathematically,

E_K=\frac{1}{2}mv^2

where,

E_K = kinetic energy of ball  

m = mass of the ball = 0.5 kg

v = velocity of ball = 10 m/s

Putting values in above equation, we get:

E_K=\frac{1}{2}\times 0.5\times (10)^2\\\\E_K=25J

Hence, the kinetic energy of the ball is 25 J

Vlad1618 [11]3 years ago
3 0
KE= .5*M*V^2
.5*.5*10^2
=25Joules
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What are (a) the lowest frequency, (b) the second lowest frequency, (c) the third lowest frequency of transverse vibrations on a
Alekssandra [29.7K]

Answer:f1 = 7.90Hz, f2= 15.811Hz, f3 = 23.71Hz.

Explanation: length of string = 10m, mass of string = 100g = 0.1kg, T= 250N

We need the velocity of sound wave in a string when plucked with a tension T, this is given below as

v = √T/u

Where u = mass /length = 0.1/ 10 = 0.01kg/m

Hence v = √250/0.01, v = √25,000 = 158.11

a) at the lowest frequency.

At the lowest frequency, the length of string is related to the wavelength with the formulae below

L = λ/2, λ= 2L.

λ = 2 * 10

λ = 20m.

But v = fλ where v = 158.11m/s and λ= 20m

f = v/ λ

f = 158.11/ 20

f = 7.90Hz.

b) at the first frequency.

The length of string and wavelength for this case is

L = λ.

Hence λ = 10m

v = 158.11m/s

v= fλ

f = v/λ

f = 158.11/10

f = 15.811Hz

c) at third frequency

The length of string is related to the wavelength of sound with the formulae below

L =3λ/2, hence λ = 2L /3

λ = 2 * 10 / 3

λ = 20/3

λ= 6.67m

v = fλ where v = 158.11m/s, λ= 6.67m

f = v/λ

f = 158.11/6.67

f = 23.71Hz.

8 0
3 years ago
A 9.0 V battery does 550 J of work transferring charge. How much charge is transferred?
jek_recluse [69]

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V = 9.0

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Q = !?

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5 0
2 years ago
A 600kg car is at rest, and then it accelerates to 5 m/s.
uranmaximum [27]

Answer:

1. 0 J

2. 7500 J

3. 7500 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Final velocity (v₂) of car = 5 m/s

Original kinetic energy (KE₁) =?

Final kinetic energy (KE₂) =?

Work used =?

1. Determination of the original kinetic energy.

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Original kinetic energy (KE₁) =?

KE₁ = ½mv₁²

KE₁ = ½ × 600 × 0²

KE₁ = 0 J

Thus, the original kinetic energy of the car is 0 J.

2. Determination of the final kinetic energy.

Mass (m) of car = 600 Kg

Final velocity (v₂) of car = 5 m/s

Final kinetic energy (KE₂) =?

KE₂ = ½mv₂²

KE₂ = ½ × 600 × 5²

KE₂ = 300 × 25

KE₂ = 7500 J

Thus, the final kinetic energy of the car is 7500 J

3. Determination of the work used.

Original kinetic energy (KE₁) = 0

Final kinetic energy (KE₂) = 7500 J

Work used =?

Work used = KE₂ – KE₁

Work used = 7500 – 0

Work used = 7500 J

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